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katen-ka-za [31]
3 years ago
12

Sum of 1+3+5+7...+103

Mathematics
1 answer:
Levart [38]3 years ago
6 0
1+3+5+7+103=119. I hope this is what you were asking for! :)
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Write a fraction that is equivalent to 6 divided by 27
faust18 [17]
27/6 because this shows that you are dividing 6 from 27.
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3 years ago
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Will give brainliest to the homie that gets it right! please help!
12345 [234]
I'm pretty sure the answer to your question is -3/5 + 4/5. C.

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Need help please...............................
Hunter-Best [27]
Note that the side adjacent to angle XYZ is given (6 cm) and that the hypo is also given (15 cm).  Thus, cos XYZ = adj / hyp = 6 cm / 15 cm  = 2/5 = 0.4.

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7 0
3 years ago
Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.
seropon [69]

Answer:

h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

Step-by-step explanation:

1) The Fundamental Theorem of Calculus in its first part, shows us a reciprocal relationship between Derivatives and Integration

g(x)=\int_{a}^{x}f(t)dt \:\:a\leqslant x\leqslant b

2) In this case, we'll need to find the derivative applying the chain rule. As it follows:

h(x)=\int_{a}^{x^{2}}\sqrt{5+r^{3}}\therefore h'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left (\int_{a}^{x^{2}}\sqrt{5+r^{3}}\right )\\h'(x)=\sqrt{5+r^{3}}\\Chain\:Rule:\\F'(x)=f'(g(x))*g'(x)\\h'=\sqrt{5+r^{3}}\Rightarrow h'(x)=\frac{1}{2}*(r^{3}+5)^{-\frac{1}{2}}*(3r^{2}+0)\Rightarrow h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

3) To test it, just integrate:

\int \frac{3r^{2}}{2\sqrt{r^3+5}}dr=\sqrt{r^{3}+5}+C

5 0
3 years ago
Katie need to buy 1kg of oranges. If each orange weighs 100g, how many total oranges does she needs to buy.
lana [24]
1kg is 1000 grams. If each orange is 100g, 10 oranges is 1000g or 1kg. The answer is B or 10 oranges.
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3 years ago
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