Write 0.060606 ... as a fraction in simplest form?

a motorist starts from O nd moves in a direction 030° for 36km.he then moves 7km towards the west .how far east his he now from

gavmur [86]

Answer:

11 km

Step-by-step explanation:

Assuming your "direction 030°" is a bearing measured clockwise from north, the amount the motorist moved east on the first leg of the journey was ...

(36 km)sin(30°) = 18 km

From that point, moving 7 km west makes his easterly position ...

18 km -7 km = 11 km . . . . east of O

_____

The sine of an angle is the ratio of the side opposite to the hypotenuse. You can find the length of the side opposite (the easterly motion) by multiplying the sine of the bearing angle by the distance of travel. A diagram can help.

5 0

3 years ago

Maurice finished 14 paintings in 5 days. He painted the same number of paintings each day. Which of the following equations repr

Nuetrik [128]

Just use the calculator on your phone

4 0

3 years ago

Read 2 more answers

A round cake has a diameter of 30 cm. Angela places the cake on a circular cake board with a diameter 5 cm longer than that of t

Stels [109]

Answer:

C = 35 pi

Step-by-step explanation:

The new diameter is 5 + 30 = 35

The circumference = pi * d

The circumference = 35*pi

5 0

3 years ago

Pls answer this...its very important for me...i have an exam coming up...and this 2 questions will come up so pls help. I WILL M

tamaranim1 [39]

Answer:

a. x = 3

b. x = 3

Step-by-step explanation:

Given

$\frac{4^{2x}}{4^x} = 64$

$(2^{2x}) = 64$

Required

Find x

Solving $\frac{4^{2x}}{4^x} = 64$

From laws of indices;

$\frac{a^{m}}{a^n} = a^{m-n}$

So;

$4^{2x-x} = 64$

$4^{x} = 64$

Write 64 in base of 4

$4^{x} = 4^3$

From laws of indices;

$if\ x^a = x^b;\ then\ a = b$

So; x = 3

Solving $(2^{2x}) = 64$

Write 64 as a base of 2

$(2^{2x}) = 2^6$

$if\ x^a = x^b;\ then\ a = b$

$2x = 6$

Divide both sides by 2

$\frac{2x}{2} = \frac{6}{2}$

$x = 3$

3 0

3 years ago

I need help on ratio of x-coordinates and ratio of y-coordinates

ad-work [718]

Answer:

Ratio of x-coordinates:

$\frac{-1}{-2}=\frac{1}{2}$

$\frac{2}{4}=\frac{1}{2}$

$\frac{-2}{-4}=\frac{1}{2}$

Ration of y-coordinates:

$\frac{2.5}{5}=\frac{1}{2}$

$\frac{1}{2}=\frac{1}{2}$

$\frac{-2}{-4}=\frac{1}{2}$

Step-by-step explanation:

The table is asking for the ratio of x-coordinates for each point (A, B, C and D) for both the image and pre-image. The ratio is the image 'x' or 'y' value ÷ the pre-image 'x' or 'y' value. Each ratio should be expressed in simplest form and should show the same pattern of dilation, or same scale factor. In this case, the second figure is 1/2 the size of the original figure.

5 0

4 years ago