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3 years ago

Expand and simplify (x-2)(x-2)(x-3)

1 answer:

6 0

$(x-2)(x-2)(x-3)$
$(x-2)^{2}(x-3)$
$x^{2} +2x*(-2)+(-2) ^{2})(x-3)$
$( 4+x^{2}+(-4)x)(x-3)$
$( x^{2} -4x+4)(x-3)$
$x^{3} - x^{2} *3-4xx+4x*3+4x-12$

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3 reds in the 10 remaining cards
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2 years ago

DedPeter [7]

9514 1404 393

Answer:

77 purple counters

Step-by-step explanation:

There are a total of 5+7=12 ratio units, so each stands for 132/12 = 11 counters. The 7 ratio units representing the purple counters stand for ...

11 × 7 = 77 purple counters

4 0

2 years ago

BabaBlast [244]

Answer:

$507.30

Step-by-step explanation:

-Given the monthly deposits are $425 and the interest rate is 3.5% for 30 years.

-The amount of the investment after 30 years is calculated as;

$A=P(1+i/n)^n, n=time \ in \ months\\\\=425(1+0.035/12)^{30\times 12}\\\\=1212.65$

-Assuming Saul started saving at age 20, his investment term will be 40 yrs.

-His investment amount is thus:

$A=P(1+i/n)^n, n=time \ in \ months\\\\=425(1+0.035/12)^{40\times 12}\\\\=1719.95$

#We subtract to find how much more he would have if he started saving at 20;

$=A_{20}-A_{30}\\\\=1719.95-1212.65\\\\=507.30$

Hence, Saul would have $507.30 more had he started saving 10 years earlier.

5 0

3 years ago

fiasKO [112]

Answer:

n(-8)=16 is the answer

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3 years ago

Fynjy0 [20]

5x -15 + 3 -8x = 13
5x -12 -8x = 13
5x -8x =13 -12
-3x = 1
x = -1/3

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2 years ago