$-3x+y=-2 \\
y-4=-6x \ \ \ |\times (-1) \\ \\
-3x+y=-2 \\
\underline{-y+4=6x} \\
-3x+y-y+4=6x-2 \\
-3x+4=6x-2 \\
-3x-6x=-2-4 \\
-9x=-6 \\
x=\frac{-6}{-9} \\
x=\frac{2}{3} \\ \\
y-4=-6 \times \frac{2}{3} \\
y-4=-4 \\
y=-4+4 \\
y=0 \\ \\
(x,y)=(\frac{2}{3},0)$

The system has one solution so it's A. consistent and independent.

7 0

3 years ago

Please help me , im so bad at this loll

Sholpan [36]

Answer:

1st: 8

3rd:0.25

4th:19

5th:1

Step-by-step explanation:

6 0

3 years ago

Find the value of x to the nearest tenth.

Svetach [21]

Cos(angle) = Adjacent Leg / Hypotenuse

cos(35) = 9 / x

x = 9 / cos(35)

x = 10.99

Rounded to nearest tenth = 11.0

6 0

4 years ago

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