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yan [13]
3 years ago
14

What is 312÷2 can someone help

Mathematics
2 answers:
Kisachek [45]3 years ago
3 0

156

Divide using a calculator or long division

Nostrana [21]3 years ago
3 0

Answer:

the answer is 156 please mark brainliest

Step-by-step explanation:

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The lovin lemon company sells a 4 gallon jug of lemonade for $24 the sweet and sour company sells an 8 pack of 1 quart bottles o
Angelina_Jolie [31]
The 8 pack of 1 quart bottles of lemonade is the higher price unit because 4 gallons equal 16 quarts. 16 divided by 2= 8 and 24 divided by 2 =12 dollars. so therefore 8 quarts of "lovin lemon" company is $12 and 8 quarts of "sweet and sour" company is $16 so THE ANSWER IS: "SWEET AND SOUR" COMPANY HAS THE HIGHER UNIT RATE.
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3 years ago
A NUMBER , TRIPLE THAT NUMBER , AND 12 ARE ADDED THE RESULT IS 32
liraira [26]
If you want to find out what that number is, then let's call it n
n + 3n (Three times the number) + 12 = 32
Simplify
4n + 12 = 32
Subtract 12 from each side
4n = 20
Divide each side by 4
n = 5


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3 years ago
Given the two points (2,4) and (-3,2), what is the slope of the line that goes through both of these points?
Andreyy89
With the formula: m=(y1-y2)/(x1-x2) you can sub in the values to get the slope (m).

m=(4-2)/(2-(-3))
   = 2/5

Therefore the slope is 2/5.
5 0
3 years ago
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Mr. Davis divided his money in the ratio 4:6 between James and Brett. James got the smaller amount of $540. How much did Brett r
sattari [20]

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$810

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3 0
3 years ago
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
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