Answer:
61.25%
Step-by-step explanation:
How many ml of 20 percent acid should be added to pure acid
to make 70 ml of 30 percent acid?
:
let x = amt of 20% mixture
then
(70-x) = amt of pure acid
:
0.20x + (70-x) =0 .30(70)
0.20x + 70 - x = 21
= 21 - 70
-0.8x =-49
x = 61.25%
x = +61.25 ml of 20% stuff
14gallons=380miles
14/380=<span>0.03684210526gallons/mile
</span>
418*<span>0.03684210526=15.4gallons
</span>
or you could cross multiply
14gallons=380miles
x gallons=418miles

380x=5852
divide both sides by 380
x=15.4 gallons
Answer:
<h2>k > 4.4</h2>
Step-by-step explanation:
