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Simplify the following expression. (19x + 4y) + (49x + 32y)

Valentin [98]

Answer:

68x + 36y

General Formulas and Concepts:

Order of Operations: BPEMDAS
Combining like terms

Step-by-step explanation:

Step 1: Define expression

(19x + 4y) + (49x + 32y)

Step 2: Simplify expression

Combine like terms (x): 68x + 4y + 32y
Combine like terms (y): 68x + 36y

4 0

3 years ago

Can someone please help me with math

Anastasy [175]

Answer:

100 gallon for every 50 mile

Step-by-step explanation:

if you look at it the 50 meet up with 100 and 50 says it's mile and 100 is gallon so you got 100 gallon for every 50 mile

5 0

3 years ago

Use the appropriate substitutions to write down the first four nonzero terms of the Maclaurin series for the binomial (1+3x)^(-1

PolarNik [594]

Answer:

First term=1

Second term=-x

Third term= $2x^2$

Fourth term = $-\frac{28}{3!}x^3$

Step-by-step explanation:

We are given that function

$f(x)=(1+3x)^{-1/3}$

We have to find the first four non zero terms of the Maclaurin series for the binomial.

Maclaurin series of function f(x) is given by

$f(x)=f(0)+f'(0)x+\frac{1}{2!}f''(0)x^2+\frac{1}{3!}f'''(0)x^3+....$

$f(0)=(1+3x)^{\frac{-1}{3}}=1$

$f'(x)=-\frac{1}{3}(1+3x)^{-\frac{4}{3}}(3)=-(1+3x)^{-\frac{4}{3}}$

$f'(0)=-1$

$f''(x)=\frac{4}{3}\times 3 (1+3x)^{-\frac{7}{3}}$

$f''(0)=4$

$f'''(x)=-4\times \frac{7}{3}\times 3(1+3x)^{-\frac{10}{3}}$

$f'''(0)=-28$

Substitute the values we get

$(1+3x)^{-\frac{1}{3}}=1-x+\frac{4}{2!}x^2+\frac{-28}{3!}x^3+...$

$(1+3x)^{-\frac{1}{3}}=1-x+2x^2+\frac{-28}{3!}x^3+...$

First term=1

Second term=-x

Third term= $2x^2$

Fourth term = $-\frac{28}{3!}x^3$

5 0

3 years ago

Identify the segment bisector of RS. Then find RS

Elena-2011 [213]

Answer:

RS = 32

Step-by-step explanation:

M is the bisector of RS , then

RM = MS , that is

6x - 2 = 3x + 7 ( subtract 3x from both sides )

3x - 2 = 7 ( add 2 to both sides )

3x = 9 ( divide both sides by 3 )

x = 3

Then

RS = 6x - 2 + 3x + 7 = 9x + 5 = 9(3) + 5 = 27 + 5 = 32

8 0

3 years ago

Read 2 more answers

In a group of 60 students, 18 students take Algebra I, 20 students take

marshall27 [118]

The Answer would be D. 12

8 0

3 years ago

Read 2 more answers