Answer:
3 square root 2.
Step-by-step explanation:
I think the answer is b (3 square root 2). the Pythagorean therom states that B^2+ B^2= C^2. we know that c squared is 36. 3 square root 2 is approximately 4.24. ( this squared is 17.98). 17.98 + 17.98 = 35.96. If i round this up, it is 36.
X= 1st integer
x+2= 2nd integer
x+4= 3rd integer
Add the integers together
x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer
Substitute x=91 to find 2nd & 3rd integers
2nd Integer
=x+2
=91+2
=93
3rd Integer
=x+4
=91+4
=95
ANSWER: The three test scores are 91, 93 and 95.
Hope this helps! :)
Answer:
12 and 52
Step-by-step explanation:
Let x and y be the 2 integers with x > y, then
x + y = 64 and
x = 3y + 16 ( 16 more than 3 times the smaller )
Substitute x = 3y + 16 into x + y = 64, that is
3y + 16 + y = 64
4y + 16 = 64 ( subtract 16 from both sides )
4y = 48 ( divide both sides by 4 )
y = 12 and x = 3(12) + 16 = 36 + 16 = 52
The 2 integers are 12 and 52
F(103)=103/103+9
103/103=1
so f(103)=1+9
THE ANSWER IS 10 :)
Answer:
Suzie's answers are incorrect.
Step-by-step explanation:
x^2+4x-12=2
+12 +12
x^2+4x=14
(if we put Suzie's answer in for x)-
2^2+4(2)=14
4+8=14
Suzie's first answer is incorrect (4+8=12)
Let's try the next one with Suzie's answer
(-6-2)(-6+6)=2
(-8)(0)=2
This answer is also incorrect. (-8*0=0)