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photoshop1234 [79]
3 years ago
9

M(3,6) is the midpoint of Rs The coordinates of S are (5,9). What are the coordinates of R? O 17, 12) O (4, 7.5) O (6, 12) O (1,

3)​
Mathematics
1 answer:
miss Akunina [59]3 years ago
8 0

Answer:

Step-by-step explanation:

(x+5)/2 = 3

x + 5 = 6

x = 1

(y+9)/2=6

y+9= 12

y = 3

(1, 3)

answer is option 4

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Simplify (*x* +2x? - 5x)+(-3x + x +1)+(3+* + 2x).
Mama L [17]

Answer:

D

Step-by-step explanation:

4x^4+3x^2-3x^3-3x+1

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3 years ago
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Tori ran 4/5 Mile in 1/5 hour. write an equation for the distance in miles Y that she ran in X hours if she ran at a constant ra
nirvana33 [79]

Answer:

y=4x

Step-by-step explanation:

Let

y ----> the distance in miles

x ----> the time in hours

using proportion

\frac{y}{x}=\frac{(4/5)}{(1/5)}

Simplify

\frac{y}{x}=\frac{4}{1}

y=4x

This is a linear direct variation

The unit rate or speed is the slope of the linear equation

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6 0
2 years ago
someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your
Lunna [17]

Answer:

Part A) The area of the figure is 24\ units^{2}

Part B) The perimeter of the figure is 20\ units

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

A=\frac{1}{2}bh

<u>Area of triangle ABD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(9-5)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

<u>Area of triangle BCD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(5-1)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

The area of the figure is

12\ units^{2}+12\ units^{2}=24\ units^{2}

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

P=AB+BC+CD+AD

we have

A(-5,1),B(-8,5),C(-5,9),D(-2,5)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units

Find the distance BC

d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units

Find the distance CD

d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units

Find the distance AD

d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units

substitute the values

P=5+5+5+5=20\ units

7 0
3 years ago
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IgorLugansk [536]

Answer:

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Step-by-step explanation:

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3 years ago
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baherus [9]

Answer:

5(7d-5)

Step-by-step explanation:

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