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blondinia [14]
3 years ago
14

WILL GIVE BRAINLIEST TO ANSWER

Mathematics
1 answer:
Anika [276]3 years ago
7 0

its x4 got it thanks give me brainliest

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BRAINLIESTTT ASAP! PLEASE HELP ME :)<br><br> please check answer..
SCORPION-xisa [38]

Answer:

B. False, they could be vertical angles

Step-by-step explanation:

Supplementary just mean when two angles form 180° (a straight line).

So ∠F and ∠G must form a straight line, and ∠G and ∠H must form a a straight line.

I drew the image out below and as you can see, angle F and H forms a vertical angle. A vertical angles is when two lines cross, the opposite angles from each others are called vertical angles.

6 0
3 years ago
3(x-6)-8x=-2 + 5(2x+1)
postnew [5]

Answer:

<u>x = -1</u>

Step-by-step explanation:

3(x - 6) - 8x = -2 + 5(2x + 1)

3x - 18 - 8x = -2 + 10x + 5

-5x - 18 = 10x + 3

-15x = 15

<u>x = -1</u>

3 0
3 years ago
Read 2 more answers
use the following graph of the function of degree 9 to identify the zeros of function and their possible multiplicities
nexus9112 [7]

Answer:

d

Step-by-step explanation:

sd

7 0
3 years ago
Need help fast please
dalvyx [7]

Answer:

13. The slope for a line that is perpendicular to the line y=4x+8 is  -1/4

14. The slope for a line that is perpendicular to the line x=-6 is 0

15. The equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin is y = - (1/2) x

16. The equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10) is y=3x-10

Step-by-step explanation:

13. What is the slope for a line that is perpendicular to the line y=4x+8?

y=mx+b

Comparing with the form slope-intercept, the slope of the given line is the coefficient of x, then the slope of the given line is 4.

A line perpendicular to y=4x+8 must have a slope opposite and inverse, then:

Slope of the perpendicular = - 1/4


14. What is the slope for a line that is perpendicular to the line x=-6?

The line x=-6 is a vertical line. A line perpendicular to the line x=-6 must be a horizontal line (Angle=0°), then:

Slope of the perpendicular = tan Angle = tan 0° = 0


15. Write the equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin.

8x-4y=12

Isolating y: Subtracting 8x both sides of the equation:

8x-4y-8x=12-8x

-4y=-8x+12

Dividing all the terms by -4:

-4y/(-4)= -8x/(-4)+12/(-4)

y=2x-3

The slope of the given line is 2

The slope of the perpendicular is m=-1/2 (opposite and inverse to the slope of the given line)

The perpendicular passes through the origin:

P1=(0,0)=(x1,y1)→x1=0, y1=0

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-0=(-1/2)(x-0)

y=(-1/2)x


16. Write an equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10).

The slope of the given line is -(1/3)

The slope of the perpendicular is m=3/1→m=3 (opposite and inverse to the slope of the given line)

The perpendicular passes through the point:

P1=(0,-10)=(x1,y1)→x1=0, y1=-10

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-(-10)=3(x-0)

y+10=3x

Isolating y: Subtracting 10 both sides of the equation:

y+10-10=3x-10

y=3x-10


 

8 0
4 years ago
What is the equation of a line through point (-4, 5) that is perpendicular to the line with equation y= -6x+4?
SVEN [57.7K]

Answer:

i will help in a bit

Step-by-step explanation:

7 0
4 years ago
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