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3 years ago

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Mathematics

1 answer:

KIM [24]3 years ago

6 0

Answer:

The Red block is the answer

Step-by-step explanation:

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lyudmila [28]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Side BC

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

$\therefore \tt \boxed{ \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} = { \bigg(\frac{BC}{EF} \bigg)}^{2} }$

❍ Putting the values, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

$\implies \tt \dfrac{64 \: {cm}^{2} }{12 \: {cm}^{2} } = { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}$

❍ By solving we get,

$\implies \tt \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }} = \bigg( \dfrac{BC}{15.4 \: cm} \bigg)$

$\implies \tt \sqrt{\dfrac{{(8 \: cm)}^{2} }{ {(11 \: cm)}^{2} }} = \bigg( \dfrac{BC}{15.4 \: cm} \bigg)$

$\implies \tt \dfrac{8 \: cm}{11 \: cm} = \dfrac{BC}{15.4 \: cm}$

$\implies \tt \dfrac{8 \: cm \times 15.4 \: cm}{11 \: cm} = BC$

$\implies \tt \dfrac{123.2 }{11 } cm = BC$

$\implies \tt \purple{ 11.2 \: cm} = BC$

Hence, BC = 11.2 cm.

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

$\rule{280pt}{2pt}$

4 0

2 years ago

Solve the following equation for a. be sure to take into account whether a letter is capitalized or not g = Ha + na

dimulka [17.4K]

Answer:

$a = \frac{g}{H+n}$

Step-by-step explanation:

Step 1: Factor

g = a(H + n)

Step 2: Divide both sides by expression in parenthesis

g/(H + n) = a

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4 years ago

What is the percent of each? Please help!!

il63 [147K]

Answer:

1 Cards = 36%

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4 Cards = 12.5%

Step-by-step explanation:

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3 years ago

What is the answer to y=3x-1/5

Aliun [14]

Standard form: -3x +5y= -1

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3 years ago

Mr.James has a cylindrical beakers that measure 4 inches in diameter and are 9 inches high .What is the volume contained within

Ksju [112]

Cylinder Volume = PI * radius^2 * height

Cylinder Volume = 3.14 * 2^2 * 9

Cylinder Volume = 113.04 cubic inches

1728.com/diamform.htm

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3 years ago

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