So average is of the first 6 tests is 82 well that means

(test1 + test2+ test3+ test4 + test5+test6)/6 = 82

so now let do some cross multiplliying

test1 + test2 + test3 + test 4 + test5 +test6 = 82*6

test1 + test2 + test3 + test 4 + test5 +test6 = 492

now lets see if we can find that 7th test score

(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5

So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute.

(492 + test7 )/7 = 80.5

test7 = (80.5*7)-492 = 71.5

7 0

2 years ago

Which histogram correctly represents the data given in this frequency table

andrezito [222]

The image is not clear you have to retake the picture I can’t see the numbers in the table

4 0

2 years ago

Read 2 more answers

What is the value of y when x = 43<br> A. 87<br> B. 85<br> C. 49<br> D. 45

BartSMP [9]

Answer:

A x

−

Step-by-step explanation:

−

3 0

2 years ago

Prove that root 7 is irrational by the method of contradiction

Alchen [17]

Let assume that $\sqrt7$ is a rational number. Therefore it can be expressed as a fraction $\dfrac{a}{b}$ where $a,b\in\mathbb{Z}$ and $\text{gcd}(a,b)=1$ .