Answer:
Step-by-step explanation:
To determine the Z - score, it is calculated as follows:
Then:
It means that there are more than 3 standar deviations below the advertised mileage.
i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
If <em>x</em> = -1, you have
2(-1) + 3 cos(-1) + <em>e</em> ⁻¹ ≈ -0.0112136 < 0
and if <em>x</em> = 0, you have
2(0) + 3 cos(0) + <em>e</em> ⁰ = 4 > 0
The function <em>f(x)</em> = 2<em>x</em> + 3 cos(<em>x</em>) + <em>eˣ</em> is continuous over the real numbers, so the intermediate value theorem applies, and it says that there is some -1 < <em>c</em> < 0 such that <em>f(c)</em> = 0.
Answer:
(A) 509.78
We need to move the decimal point after the first non-zero digit
So,
=> 5.0978 × 10² (Since the decimal point is moved two places to the left)
(B) 0.0289
Again after the first non-zero digit:
So, it becomes:
=> 2.89 × 10⁻² (Since the decimal point is moved 2 places to the right so it will be negative also)
In order to get who was right we need to solve the expression:
2a^2b(-2ab^3)^-2
The above can be written as fraction to get:
(2a^2b)/(-2ab^3)^2
=(2a^2b)/(4a^2b^6)
=1/2(a^(2-2)b^(1-6))
=1/2a^0b^-5
=1/2b^(-5)
This implies that neither of the was right
