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4 years ago

A. I, III, II b. II, I, III c. II, III, I d. III, I, II

Mathematics

1 answer:

sleet_krkn [62]4 years ago

7 0

I Believe That The Answer Is C .

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Paulo works at the United Nations. He researched what percent of the world's population lives on each continent. He surveys a sa

Fofino [41]

Answer:

confidence interval using a two sample t test between percents

Step-by-step explanation:

confidence interval using a two sample t test between percents This can be used to compare percentages drawn from two independent samples in this case employees. It is used to compare two sub groups from a single sample example the population on the planet

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3 years ago

Which is a better buy? 5000 sqft of lawn food for $11.99 or 12500 sqft of lawn food for $19.99? Show proof.

xz_007 [3.2K]

12500 cause 5000 goes into 12500 twice and it would be 24$ for 10000 sqft and then another 6 so 30$ cause 2500 is half of 5000

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3 years ago

Which list shows the numbers ordered from least to greatest?

Lorico [155]

Answer:

:::::::::::::"::::::

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3 years ago

How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy

Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

$n \cdot (n+1) < 40000$

Now we solve this inequation to the highest value of $n$ that satisfy the inequation:

$n^{2}+n < 40000$

$n^{2}+n -40000$

The Quadratic Formula shows that roots are:

$n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}$

$n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}$

$n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}$

$n_{1} \approx 199.501$

$n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}$

$n_{2} \approx -200.501$

Only the first root is valid source to determine the highest possible value of $n$ , which is $n_{max} = 199$ . Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

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3 years ago

Who was Novia scotias reform leader

qaws [65]

Step-by-step explanation:

Their leaders were Charles Tupper and Adams george Archibald

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3 years ago