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tangare [24]
3 years ago
13

A. I, III, II b. II, I, III c. II, III, I d. III, I, II

Mathematics
1 answer:
sleet_krkn [62]3 years ago
7 0
I Believe That The Answer Is C .
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I got 2 km per hour

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-7.79+9.55 what does this equal?
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Vinvika [58]

Answer:

x = -15/2

Step-by-step explanation:

For this problem, we will simply use equation properties to solve for x.

2x - 5 = -20

2x - 5 + 5 = -20 + 5

2x = -15  ( Add positive 5 to both sides )

2x * (1/2) = -15 * (1/2)

x = -15/2  ( Multiply both sides by 1/2)

Hence, the solution to x is -15 / 2.

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A maritime flag is shown. What is the area of the shaded part of the flag? Explain
Rom4ik [11]

Answer:

<em></em>Area = 72in^2<em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate  the Area:</em>

<em></em>Area_1 = Length * Width<em></em>

<em></em>Area_2 = 8in * (6in + 6in)<em></em>

<em></em>Area_2 = 8in * 12in<em></em>

<em></em>Area_1 = 96in^2<em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em>Area_2 = \frac{1}{2} * base * height<em></em>

<em></em>Area_2 = \frac{1}{2} * (6in + 6in) * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 12in * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 48in^2<em></em>

<em></em>Area_2 = 24in^2<em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em>Area = Area_1 - Area_2<em></em>

<em></em>Area = 96in^2 - 24in^2<em></em>

<em></em>Area = 72in^2<em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0
2 years ago
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