2 years ago

In a triangle ABC, AB = 7, AC = 8, BC = 3, what is cos(A)?

1 answer:

6 0

Use the cosine rule.
c=AB=7
b=AC=8
a=BC=3
a^2=b^2+c^2-2bc(cos(A))
=>
cos(A)=(b^2+c^2-a^2)/(2bc)
=(7^2+8^2-3^2)/(2*7*8)
=13/14
=0.9286

You might be interested in

harina [27]

C.264.4 that should answer your question

4 0

2 years ago

PIT_PIT [208]

Answer: they are both the same fraction

3 0

2 years ago

STatiana [176]

Divide 120 by 2 or divide 120 by 60

3 0

3 years ago

ch4aika [34]

The GCF of 27 and 18 would be 9. It is the largest or greatest common factor that can be evenly divided by in both the numbers 27 and 18.

7 0

2 years ago

vfiekz [6]

Step 1

given

Step 2

$\angle HKM \cong \angle OKM, \angle HMK \cong \angle OMK$

Step 3

$\overline{KM} \cong \overline{KM}$

Reason: Reflexive property

Step 4

ASA

8 0

1 year ago