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3 years ago

HELP ME PLEASEEEEEEEE I WILL MARK BRAINLIEST TO CORRECT ANSWER

Mathematics

2 answers:

Hitman42 [59]3 years ago

6 0

Answer:

Step-by-step explanation:

$4a+7\\\\a=\frac{1}{2}\\\\=4[\frac{1}{2}]+7\\\\=2+7\\\\=9$

Burka [1]3 years ago

6 0

Answer: a = 9

Step-by-step explanation:

so, we can start with multiply 4 by 1/2 (we substitute 1/2 for the a), which gives us 2. then, we simply add 7. that gets us to a = 9.

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What is the answer to this problem?

Nastasia [14]

Answer is c because if count the sides of how many spaces are there

8 0

3 years ago

line segment AB has endpoints A (7.5,4.2) and B (2.3,5.4). Find the coordinates of the point that divides the line segment direc

Marrrta [24]

9514 1404 393

Answer:

(6.2, 4.5)

Step-by-step explanation:

We want, for some point P, ...

(P -A) / (B -P) = 1 / 3

3(P -A) = (B - P) . . . . . multiply by 3

4P = B +3A . . . . . . . . add P+3A

P = (B +3A)/4 . . . . . . .divide by 4

Filling in the coordinate values, we can find P to be ...

P = ((2.3, 5.4) +3(7.5, 4.2))/4 = (2.3+22.5, 5.4+12.6)/4

P = (6.2, 4.5)

5 0

3 years ago

1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6

meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

x= -3

Putting value of x in equation 1

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

Let

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ = A $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = X and $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$ = B

Then AX= B

or X= A⁻¹ B

where A⁻¹= adj A/ ║A║ where mod A≠ 0

adj A= $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$ $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}42\\0\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-3\\0\\\end{array}\right]$

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0

3 years ago

Use the law of sines to find m

Rufina [12.5K]

the answer is c. 40.5

5 0

3 years ago

What is the equation of a line when the slope is -1/2 and the y-intercept is 0.

tangare [24]

Answer:

y = -1/2x + 0

y = mx+b

Step-by-step explanation:

8 0

3 years ago