This is really confusing. Thanks for helping.

1 answer:

5 0

Count change of signs to tell positive roots
then replace x with -x and evaluate, then count change in sign for negative roots

initially
+, -, -, +, +, -
3 changes
3 or 1 positive roots

replacing x with -x
-,-,+,+,-,-
2 changes
2 or 0 negative roots

B is answer

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F(x) = -x + 4 and g(x) = 6x + 3, find (f(x) - g(x)) A. -5x-1 B. 5x +1 C. -7x +1

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Answer:

Step-by-step explanation:

f(x) - g(x)

= - x + 4 - (6x + 3)

= - x + 4 - 6x - 3 ← collect like terms

= - 7x + 1 → C

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PLEASE help me ASAP i give brainliest!

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Answer:

scatter plot A: -0.90

scatter plot B: 0.89

scatter plot C: -0.76

scatter plot D: 0.55

Step-by-step explanation:

if the line is going down, it's negative and if it goes up it's positive. The closer the points are the higher the number.

HOPE THIS HELPS!!

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A small company’s net income for the first six months of the year was $76,500 and for the last six months it was $100,000. What

mr Goodwill [35]

Answer:153/200

Step-by-step explanation:

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3 years ago

In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i

PilotLPTM [1.2K]

Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,

was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

$\bf \displaystyle \int -32\cdot dt\implies -32t+C
\\\\\\
\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
\\\\\\
-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
\\\\\\
\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
\\\\\\
\textit{the initial \underline{position} was 400ft away at 0secs}
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-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}$

when will it reach the ground level? let's set s(t) = 0

$\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
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25=t^2\implies \boxed{5=t}$

part B) check the picture below

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