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NNADVOKAT [17]
3 years ago
6

The circumference of a circle is 9m What is the area of the circle?

Mathematics
1 answer:
vazorg [7]3 years ago
3 0

Answer:

Cai on kgpkvugcg7 vgu ygvhy6vgvh7

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hammer [34]
The grandfather would be your parents.Hope it helps :)
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3 years ago
I NEED HELP IM IN CLASS RN PLEASEE HELP! WILL GIVE BRIANLIEST!
fgiga [73]

Answer:

y=x+12

Step-by-step explanation:

Well the slope is -4/-4 =1

We plug it into the formula, y=mx+b, but m=1

So it is y=1x+b

We know the points, so we plug y and x in which is:

-4=-4*4+b

-4=-16+b

b=12

So the point slope form of that is y=x+12

4 0
4 years ago
I need help ON THIS PLS
Anit [1.1K]

Answer:

No, because the ratio of pay to hours is not the same for each pair of value.

8 0
3 years ago
A baker is building a rectangular solid box from cardboard to be able to safely deliver a birthday cake. The baker wants the vol
k0ka [10]

The length of the rectangular delivery box must be equal to 4 inches.

Let the length of the box be L.

Let the width of the box be W.

Let the height of the box be H.

<u>Given the following data:</u>

  • Volume of box = 224 cubic inches.

Translating the word problem into an algebraic expression;

W = 3 + L  ......equation 1

H = 4 + L  ......equation 2.

Mathematically, the volume of a rectangular solid is given by the formula;

Volume = length * width * height  .....equation 3.

Substituting the values into equation, we have;

224 = L * (3 + L) * (4 + L)\\\\224 = (3L + L^{2})* (4 + L)\\\\224 = 12L + 3L^{2} + 4L^{2} + L^{3} \\\\224 = 12L + 7L^{2} + L^{3}

Rearranging the polynomial, we have;

L^{3} + 7L^{2} +  12L - 224 = 0

We would apply the remainder theorem to solve the polynomial.

According to the remainder theorem, if a polynomial P(x) is divided by (x - r) and there is a remainder R; then P(r) = R.

When x = 3

(x - 3) = 0\\x = 3

P(3) = 3^{3} + 7(3^{2}) + 12(3) - 224\\\\P(3) = 27 + 7(9)  + 36 - 224\\\\P(3) = 27 + 63 + 36 - 224 = -98 \neq 0

We would try with 4;

P(4) = 4^{3} + 7(4^{2}) + 12(4) - 224\\\\P(4) = 64 + 7(16)  + 48 - 224\\\\P(4) = 64 + 112 + 48 - 224\\\\P(4) = 224  - 224 = 0

Therefore, 4 is one of its roots.

Hence, the length of the rectangular delivery box must be equal to 4 inches.

Find more information on polynomial here: brainly.com/question/10689855

3 0
3 years ago
Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time
kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0
3 years ago
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