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WINSTONCH [101]
2 years ago
13

Which results are expected in a personality test but not a skills assessment?

Computers and Technology
1 answer:
dimaraw [331]2 years ago
6 0

Answer:

openness, conscientiousness, extraversion

Explanation:

A personality test is defined as a test that is used to assess the human personality. It is designed as the techniques to measure characteristics patterns of the traits that various people shows at different situations or environments.

A skill assessment test is used to test the abilities and the skill sets of people to perform a particular tasks given to them. It is measuring the knowledge and skills of a person.

The personality test are carried out to test how human behave and what traits they show in certain conditions. Thus openness, extra version and conscientiousness are some of the traits that people usually shows in a personality test. Thus they are the results that are expected by an individual of a personality test.

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(tco 3) what vbscript boolean operator could be used to replace the nested selection structure in this pseudocode? if empmedical
Leto [7]
You want both conditions to be true, so you can "And" them.
In vbscript, the and is written as "And" (not as && like other languages), so you get:

<span>If (empmedicalins = "y") And (empdentalins = "y") Then
    print empidnumber, emplastname, empfirstname
Endif</span>
3 0
3 years ago
A group of statisticians at a local college has asked you to create a set of functions that compute the median and mode of a set
Vanyuwa [196]

Answer:

from functools import reduce

def mean(mylist):

   score = reduce(lambda x,y: x + y, mylist)/ len(mylist)

   return score

def median(mylist):

   sorted(mylist)

   list_len = len(mylist) % 2

   i = round(len(mylist)/2)

   x = len(mylist)//2

   if list_len == 0:

       median = (mylist[x] + mylist[x+1]) / 2  

   else:

       median = mylist[i]

   return median

def mode(mylist):

   unique = set(mylist)

   unique = list(unique)

   collector = [mylist.count(key) for key in unique]

   maxi = max(collector)

   loc = collector.index(maxi)

   return unique[loc]

def main():

   scores = input( 'Enter list of numbers: ').split(",")

   scores = [int(score) for score in scores]

   

   operation = input('Enter operation: ')

   operator = ['mean', 'median', 'mode']

   

   for x in iter(list, 0):

       if operation in operator:

           break

       print("Invalid operation: ")

       operation = input('Enter operation')

   

   index_loc = operator.index(operation)

   

   if index_loc == 0:

       return mean(scores)

   elif index_loc == 1:

       return median(scores)

       #return np.median(scores)  can be used of the defined function

   elif index_loc == 2:

       #return stats.mode(scores)[0]  can be used of the defined function

       return mode(scores)

print( main( ) )

Explanation:

The main python function calls conditionally three statistical functions namely mean, median and mode. It prompts for user input for a list of integer numbers and a function name name to return the corresponding result.

8 0
2 years ago
Which of the main value components are contained in the value proposition "SportsAde offers serious athletes a great-tasting way
Elina [12.6K]

Answer:

Explanation:unique difference/benefits

- "a great-tasting way to stay hydrated during exercise" this is the benefit statement

2. product/service category or concept is

- the drink

3. target market

- "serious athletes" is the target market

4. offering name or brand is

- SportsAde

5 0
3 years ago
Need help asapppppppppp
TEA [102]

Answer:

artistic

Explanation:

because being it is considered a art

7 0
3 years ago
Read 2 more answers
1. Scrieţi un program care citeşte un număr natural n şi determină produsul cifrelor impare ale lui n. De exemplu, pentru n = 23
saveliy_v [14]

Answer:

1.  

num1 = input("Enter the value of n")  

n = int(num1)  

def calc(n):  

Lst = []  

while n > 0:  

remainder = n % 10  

Lst.append(remainder)  

quotient = int(n / 10)  

n = quotient  

i = len(Lst) - 1  

sum = 1  

for i in range(0, len(Lst)):  

if(i % 2 != 0):  

sum *=Lst[i];  

else:  

continue  

print(sum)  

return(0)  

\ r2

num=input("Enter the value of n")

arr=[12,-12,13,15,-34,-35,35,42]

def div7positive():

  sum = 0

  m = 0

  i = 0

  while m <= 7:

      if(arr[i]>=0 and arr[i]%7 == 0):

          sum +=arr[i]

      i = i + 1

      m += 1

       

   

  print("sum of number divisible by 7 and positive is", +sum);

div7positive()

\ r

\ r3.Write an algorithm that reads a natural number n and calculates the sum:

\ rS = 1 / (1 * 2) + 1 / (2 * 3) + 1 / (3 * 4) +… + 1 / ((n-1) * n)

\ r

num=input("Enter the value of n")

def sumseries():

  sum = 0

  m= 0

  while m <= 7:

      sum +=1/((int(num)-1)*int(num))

      m += 1

  print("sum of series is", +sum)

sumseries()

\ R4. Read a natural number n. Calculate the sum of its own divisors n. For example, for n = 12, the sum of its own divisors is 2 + 3 + 4 + 6 = 15

num=input("Enter the value of n")

def sumdivisors():

  sum = 0

  m= 2

  while m <= int(num):

      if int(num) % m == 0:

          sum += m

      m += 1

  print("sum of divisors is", +sum)

sumdivisors()\ r

\ R5. We read a natural number n and then whole numbers. Calculate and display the sum of the natural numbers between 10 and 100. For example, if n = 5 and then read 30, –2, 14, 200, 122, then the sum will be 44 (that is, 30 + 14).

\ r

Lst = []  

num=input("Enter the value of n")

i = 0

while i<= int(num):

  num1=input("Enter the element of array")

  Lst.append(int(num1));

  i += 1

def numbet0and100():

  sum = 0

  m= 0

  while m <= int(num):

      if Lst[m] <= 100 or Lst[m] >=0:

          sum += Lst[m]

      m += 1

  print("sum of numbers between 0 and 100 is", +sum)

numbet0and100()

\ R6. A natural number n of maximum 4 digits is read. How many digits are in all numbers from 1 to n? For example, for n = 14 there are 19 digits, and for n = 9 there are 9 digits.

\ r

num = input("Enter the value of n")

n = int(num)

print(“sum as required is:” (n -9) + n)  

 

\ R7. Read the natural numbers n and S, where n can be 2, 3, 4 or 5. Show all the numbers of n digits that have the numbers in strictly ascending order, and the sum of the digits is S. For example, for n = 2 and S = 10, 19, 28, 37, 46 will be displayed.

num = input("Enter the value of n")

n = int(num)

Lst = []

def calc(n):

  i = 1

  total = pow(10,n)

  while i <= total:

      j = i

      while j > 0:

          remainder = j % 10  

          Lst.append(remainder)

          quotient = int(j / 10)

          if quotient > 0:

              j = quotient

          else:

              length = len(Lst) - 1

              sum = 0

              while length >= 0:

                  sum += Lst[length]

                  length = length - 1

              if sum == pow(10,n):

                  print(j)

              k = len(Lst)

              del Lst[0:k]

      i = i + 1

  return(0)

calc(n)

\ r

\ R8. We consider the row 1, 1, 2, 3, 5, 8, 13, ... in which the first two terms are 1, and any other term is obtained from the sum of the preceding two. Write an algorithm that reads a natural number n and displays the first n terms of this string. For example, for n = 6, 1, 1, 2, 3, 5, 8 will be displayed.

\ r

nterm = int(input("What number of terms do you want?"))

a, b = 0, 1

totalcount = 0

if nterm <= 0:

 print("Please input a positive number")

elif nterm == 1:

 print("Fibonacci number upto which",nterm,":")

 print(a)

else:

 print("Fibonacci series:")

 print(nterm)

 while totalcount < nterm:

     print(a)

     nth = a + b

     a = b

     b = nth

     totalcount += 1

 

\ 9. Write an algorithm that reads two natural numbers n1 and n2 and displays the message "yes" if the sum of the squares of the digits of n1 is equal to the sum of the numbers of n2 or "no" otherwise. For example, for n1 = 232 and n2 = 881, "yes" will be displayed, and for n1 = 45 and n2 = 12, "no" will be displayed.

num1 = input("Enter the value of n")

num3 = input("Enter the value of n")

n = int(num1)

num2 = int(num3)

def calc(n):

  Lst = []

  while n > 0:

      remainder = n % 10  

      Lst.append(remainder)

      quotient = int(n / 10)

      n = quotient

       

  i = len(Lst) - 1

  sum = 0

  while i >= 0:

      sum += Lst[i]* Lst[i]

      i = i - 1

  return(sum)

def calc1(num2):

  Lst = []

  while num2 > 0:

      remainder = num2 % 10  

      Lst.append(remainder)

      quotient = int(num2 / 10)

      num2 = quotient

       

  i = len(Lst) - 1

  sum = 0

  while i >= 0:

      sum = Lst[i] + Lst[i]

      i = i - 1

  return(sum)

a = calc(n)

b = calc1(num2)

if a == b:

  print("yes")

else:

  print("No")

\ r

\ R10. Write an algorithm that reads a natural number n and displays the message "yes" if all of its n numbers are distinct, or "no" if n does not have all the distinct digits. For example, for n = 37645 it will display "yes" and for 23414 it will show "no".

\ r

num1 = input("Enter the value of n")

n = int(num1)

def calc(n):

  Lst = []

  while n > 0:

      remainder = n % 10  

      Lst.append(remainder)

      print( remainder)

      quotient = int(n / 10)

      n = quotient

       

  flag = 1

  for i in range(0, len(Lst)):

      for j in range(i+1, len(Lst)):    

          if Lst[i] == Lst[j]:    

              flag = 0

              break

           

  if flag == 1:

      print("YES")

  else:

      print("NO")

  return(0)

Explanation:

Please check answer.  

3 0
2 years ago
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