Answer:
Selecting a new layout from the task pane
Explanation:
Answer:
Think of a firewall as your own personal security guard. The firewall will block unapproved websites from talking to your computer and will stop your computer from talking to unapproved/unnecessary websites. Hope this helps!
Explanation:
<h2>Option D: a call to a private method of the superclass</h2>
Explanation:
Option a: a method with the "same signature" is allowed in the subclass. There will not be any confusion because the object which is trying to call the method will decide whether to call the sub class or super class.
Option b: a call to a super class constructor is possible because, when you create an object of sub class automatically the super class constructor will be called. Even the sub class constructor can call the super class constructor explicitly.
Option c: A subclass can create method that's not defined by the super class
Option D: a private method is private inside the class and hence even the object of that class cannot access.
Answer:
No, the receiver cannot be absolutely certain that no bit errors have occurred. This is because of the manner in which the checksum for the packet is calculated. If the corresponding bits (that would be added together) of two 16-bit words in the packet were 0 and 1 then even if these get flipped to 1 and 0 respectively, the sum still remains the same. Hence, the 1s complement the receiver calculates will also be the same. This means the checksum will verify even if there was transmission error
Explanation:
Answer:
The answer is provided in the form of explanation
Explanation:
A page fault occurs means that the required page is not in main memory. First OS check for
page in the cache memory, if the page is present then retrieved but if not present then check for
page in main memory and if the page is not present here too then it searches for page in hard
drive. To calculate the expected time, the following formula is used:
Cache hit ratio = 95% = 0.95
Cache miss ratio = 5% = 0.05
Cache access time = 2 millisecond
The average access time of hard drive = 30 milliseconds
Expected time = Hit ratio (cache access time +memory access time) + Miss ratio (cache
access time + 2 * memory access time)
= 0.95 (2+30) + 0.05 (2+2*30)
= 0.95 (32) + 0.05(62)
=30.4 + 3.1
= 33.5 millisecond
Expected time = cache hit ratio * cache access time + (1 – hit ratio) * cache miss ratio
= 0.95*2+(1-0.95)*0.05
= 1.9025
