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3 years ago

Which of the following typically have the highest auto insurance premiums?

1 answer:

7 0

Newly licensed drivers and young drivers typically have the highest insurance bill because it's been proven that these people are more likely to total their car or get into an accident rather than people who have been driving for 20+ years.

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2 years ago

PA theme is a major message that a writer convoys through a text. you have explored many themes in the hobbit one theme in the n

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The Hobbit’s main theme is Bilbo’s development into a hero, which more broadly represents the development of a common person into a hero. At the beginning of the story, Bilbo is timid, comfortable, and complacent in his secure little hole at Bag End. When Gandalf talks him into embarking on the quest with Thorin’s dwarves, Bilbo becomes so frightened that he faints. But as the novel progresses, Bilbo prevails in the face of danger and adversity, justifying Gandalf’s early claim that there is more to the little hobbit than meets the eye.??????

Explanation:

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2 years ago

Software that communicates with the hardware and allows other programs to run. It is comprised of system software, or the fundam

alukav5142 [94]

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Explanation:

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2 years ago

Two cars A and B leave an intersection at the same time. Car A travels west at an average speed of x miles per hour and car B tr

drek231 [11]

Answer:

Here is the C++ program:

#include <iostream> // to use input output functions

#include <cmath> // to use math functions like sqrt()

#include <iomanip> //to use setprecision method

using namespace std; //to access objects like cin cout

int main () { //start of main function

double speedA; //double type variable to store average speed of car A

double speedB; //double type variable to store average speed of car B

int hour; //int type variable to hold hour part of elapsed time

int minutes; //int type variable to hold minutes part of elapsed time

double shortDistance; // double type variable to store the result of shortest distance between car A and B

double distanceA; //stores the distance of carA

double distanceB; //stores the distance of carB

double mins,hours; //used to convert the elapsed time

cout << "Enter average speed of car A: " << endl; //prompt user to enter the average speed of car A

cin >> speedA; //reads the input value of average speed of car A from user

cout << "Enter average speed of car B: " << endl ; //prompt user to enter the average speed of car B

cin >> speedB; //reads the input value of average speed of car A from user

cout << "Enter elapsed time (in hours and minutes, separated by a space): " << endl; //prompts user to enter elapsed time

cin>> hour >> minutes; //reads elapsed time in hours and minutes

mins = hour * 60; //computes the minutes using value of hour

hours = (minutes+mins)/60; //computes hours using minutes and mins

distanceA = speedA * (hours); // computes distance of car A

distanceB = speedB * (hours); //computes distance of car B

shortDistance =sqrt((distanceA * distanceA) + (distanceB * distanceB)); //computes shortest distance using formula √[(distanceA)² + (distanceB)²)]

cout << "The (shortest) distance between the cars is: "<<fixed<<setprecision(2)<<shortDistance;

//display the resultant value of shortDistance up to 2 decimal places

Explanation:

I will explain the program with an examples:

Let us suppose that the average speeds of cars are:

speedA = 70

speedB = 55

Elapsed time in hours and minutes:

hour = 2

minutes = 30

After taking these input values the program control moves to the statement:

mins = hour * 60;

This becomes

mins = 2 * 60

mins = 120

hours = (minutes+mins)/60;

hours = (30 + 120) / 60

= 150/60

hours = 2.5

Now the next two statements compute distance of the cars:

distanceA = speedA * (hours);

this becomes

distanceA = 70 * (2.5)

distanceA = 175

distanceB = speedB * (hours);

distanceB = 55 * (2.5)

distanceB = 137.5

Next the shortest distance between car A and car B is computed:

shortDistance = sqrt((distanceA * distanceA) + (distanceB * distanceB));

shortDistance = sqrt((175 * 175) + (137.5 * 137.5))

= sqrt(30625 + 18906.25)

= sqrt(49531.25)

= 222.556173

shortDistance = 222.56

Hence the output is:

The (shortest) distance between the cars is: 222.56

3 0

3 years ago