Answer:
% here x and y is given which we can take as
x = 2:2:10;
y = 2:2:10;
% creating a matrix of the points
point_matrix = [x;y];
% center point of rotation which is 2,2 here
x_center_pt = x(2);
y_center_pt = y(2);
% creating a matrix of the center point
center_matrix = repmat([x_center_pt; y_center_pt], 1, length(x));
% rotation matrix with rotation degree which is 45 degree
rot_degree = pi/4;
Rotate_matrix = [cos(rot_degree) -sin(rot_degree); sin(rot_degree) cos(rot_degree)];
% shifting points for the center of rotation to be at the origin
new_matrix = point_matrix - center_matrix;
% appling rotation
new_matrix1 = Rotate_matrix*new_matrix;
Explanation:
We start the program by taking vector of the point given to us and create a matrix by adding a scaler to each units with repmat at te center point which is (2,2). Then we find the rotation matrix by taking the roatational degree which is 45 given to us. After that we shift the points to the origin and then apply rotation ans store it in a new matrix called new_matrix1.
Answer:
The correct code to this question can be de4fined as follows:
double power;
power = Math.pow(base, exp);
Explanation:
In the given question the choices were missing, that's why we defined the correct code only.
- In the given code a two double variable "base and exp" is declared, that input the value from the user-side, and store its value into there respective variables.
- In the next step, "power", that is a double variable is declared, which uses the "Math.pow" function that calculates given values power and prints its value.
please find the attachment of the full code.
<span> In a network that uses WPA2-PSK encryption you can bypass the encryption by using the weakness in the WPA2-PSK system and that is the following:the encrypted password is shared in what is known as the 4-way handshake. </span> When a client authenticates to the access point, the client and
the AP go through a 4-step process of authentication.
