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3 years ago

In the following image, AB is parallel to DC, and BC is a transversal intersecting both parallel lines.

Mathematics

1 answer:

Ulleksa [173]3 years ago

6 0

Answer:

In the following image, AB is parallel to DC, and BC is a transversal intersecting both parallel lines.

and the angle marked q° are ________angles.

The angles marked p° and q° are ________

The angle marked p° and are _______angles.

The angles marked q° and n° are _______angles.

The angles marked n° and m° are _______angles.

DONT ANSWER UNLESS YOU KNOW IT

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Given h(t) = -2(t+ 5)^2 +4, find h(-8).

bekas [8.4K]

Answer:

Substitute -8 as x into the equation.

h(-8)=-2(-8+5)^2+4

h(-8)=-2(-3)^2+4

h(-8)=-2(9)+4

h(-8)=-18+4

h(-8)=-14

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2 years ago

At the city museum, child admission is $ 5.30 and adult admission is $ 8.50 . On Tuesday, 162 tickets were sold for a total sale

zaharov [31]

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3 years ago

G(x) = 2x – 4 h(x)=x²-3 Find (g.h)(5)

Mariulka [41]

Answer:

Step-by-step explanation:

This is asking you to plug in the value of h(5) into g(x). First solve for h(5)

x^2-3 = h(x)

5^2-3= 22

h(5) = 22

h(5) is 22. So now, plug that into g(x).

g(h(5)) = 2(22)-4

44-4=40

(g.h)(5) is 40.

4 0

2 years ago

The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm^2/

VARVARA [1.3K]

Answer:

The base is decreasing at 2 cm/min.

Step-by-step explanation:

The area (A) of a triangle is given by:

$A = \frac{1}{2}bh$ (1)

Where:

b: is the base

h: is the altitude = 10 cm

If we take the derivative of equation (1) as a function of time we have:

$\frac{dA}{dt} = \frac{1}{2}(\frac{db}{dt}h + \frac{dh}{dt}b)$

We can find the base by solving equation (1) for b:

$b = \frac{2A}{h} = \frac{2*120 cm^{2}}{10 cm} = 24 cm$

Now, having that dh/dt = 1 cm/min, dA/dt = 2 cm²/min we can find db/dt:

$2 cm^{2}/min = \frac{1}{2}(\frac{db}{dt}*10 cm + 1 cm/min*24 cm)$

$\frac{db}{dt} = \frac{2*2 cm^{2}/min - 1 cm/min*24 cm}{10 cm} = -2 cm/min$

Therefore, the base is decreasing at 2 cm/min.

I hope it helps you!

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2 years ago

Solve for k. (k)4+ 3= 14 k=

r-ruslan [8.4K]

Solving for "K" , got it! :)
I'll make it easier to solve

(k)4+3-14=?
? = 0

4(k)-11 = 0

Take off the '0' and the addition symbol so we can add from 11 on your sides

4(k) - 11
+11 +11
---- ----
15k. 22
⬆ This would be your answer for k

4(k) = 11
÷4 ÷4
--- ----
1K ?

K = 11/4 (for fraction)
K = 2.75 (as a decimal)

5 0

3 years ago

Read 2 more answers