To have a weight of 2.21N., the ball's mass is (2.21/9.8) = .226kg.
<span>a) d = 1/2 (vt), = 1/2 (18 x .17), = 1.53m. </span>
<span>b) Acceleration of the ball = (v/t), = 18/.17, = 105.88m/sec^2. </span>
<span>f = (ma), = .226 x 105.88, = 23.92N. </span>
Answer:
- f⁻¹(x) = (x + 1) / (x - 2)
- f⁻¹(1 ) = - 2
Step-by-step explanation:
<u>Given function:</u>
- f(x) = (2x + 1) / (x - 1)
<u>Find its inverse, substitute x with y and f(x) with x, solve for y:</u>
- x = (2y + 1) / (y - 1)
- x(y - 1) = 2y + 1
- xy - x = 2y + 1
- xy - 2y = x + 1
- y(x - 2) = x + 1
- y = (x + 1) / (x - 2)
<u>Substitute y with f⁻¹(x):</u>
- f⁻¹(x) = (x + 1) / (x - 2)
<u>Find f⁻¹(1 ):</u>
- f⁻¹(1 ) = ( 1 + 1) / (1 - 2) = 2 / - 1 = - 2
Take 2 coordinates
Slope'-
Equation in point slope form
- y-0=6/7(x-1)
- 7y=6x-6
- y=6/7x-6/7
Answer:
The solution required per dosage is 3 mL and 9.175 mL of solution is required for the recommended dosage in a day.
Step-by-step explanation:
As the weight of the child is given as 27 lbs. Converting it to kgs as
1 kg =2.2042 lb
So 27 lbs=27/2.2042 kg
The weight of the kid in kg is 12.247 kg.
As the recommended dosage is 0.3 mg/kg/hour so for the weight of the kid the recommended dosage for the day is given as
Recommended dosage=0.3*12.247 =3.67 mg per day
As the concentration is given as 2 mg/5mL
So for each dose the solution is found as
Solution per dose is as Dose Value/Concentration=1.2/(2/5)=3 mL
So the solution required per dosage is 3 mL
Now for the solution required per day is given as
Solution per day is as =Dose Value/Concentration=3.67/(2/5)=9.175 mL
So 9.175 mL of solution is required for the recommended dosage in a day.
