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Mama L [17]
3 years ago
11

Someone please help me with this!

Mathematics
1 answer:
tigry1 [53]3 years ago
5 0

Answer:

remove the bracket on the other side by multiplying 180 by (2-n)

subtract 360 from 1260 to remain with -180n on the other side

divide both sides by -180n

then n become -5

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Two points A (-2, 9) and B (4, 8) lie on a line l. (i) Find the slope of the line l. (2)marks (ii) Find the coordinates of the m
White raven [17]

Answer :

  • 1 (i).
  • slope \:  =  -  \frac{1}{6}
  • (ii).
  • midpoints \:  = (1 \:  \:  \frac{17}{2} )
  • (iii) .
  • distance \:  =  \sqrt{37}
  • 2(i).
  • slope \:  = 2
  • gradient \:  =  -  \frac{1}{2}
  • I Hope it helps :)

8 0
3 years ago
Point (k, -3) lies on the line whose equation is x-2y=-2. What is the value of k?
natita [175]

Answer:

Substitute, <em><u>y = -3</u></em> and <em><u>x = k</u></em> on the equation.

=> k - 2×(-3) = -2

=> k = -2 + (-6)

=> k = - 8

=================

<h2>HOPE U UNDERSTOOD</h2><h3>MARK AS BRAINLIEST ONE</h3>

Any Doubts? Please COMMENT

7 0
3 years ago
What number should be added to both sides of the equation to complete the square x2 + 8x = 17 (x2 is an exponent so x squared by
Arte-miy333 [17]
The answer I believe would be 2
7 0
3 years ago
Help please!!!!!!!!!!!!!!
marshall27 [118]

Step-by-step explanation:

as in the other problem, the table describes mutually exclusive attributes.

so, we can simply sum the numbers up to get the total number of students :

3+9+2+16 = 30 students.

so, when picking a random student, we have 30 possibilities.

now, how many of those 30 have the desired attributes (to have a brother AND a sister) ?

I see 3 in the table.

so, the probability to pick a student that has a brother and a sister is

3/30 = 1/10 = 0.1

3 0
2 years ago
9 friends are lining up. Joe, Susan, John, and Meredith must be beside each other. How many ways can they line up?
ZanzabumX [31]
<h3>Answer:  17,280</h3>

This is one single number slightly over 17 thousand.

You may need to erase the comma when typing the answer in.

=========================================================

Explanation:

Let's say that another person steps in for Joe, Susan, John, and Meredith. I'll refer to this person as the teacher (perhaps these 9 friends are students on a field trip).

The 9 friends drops to 9-4 = 5 people when those four named people leave the group temporarily. Then it bumps up to 5+1 = 6 people when the teacher steps in. Wherever the teacher is located, the four friends that left will replace the teacher. This guarantees that those four friends stick together.

There are 6! = 6*5*4*3*2*1 = 720 ways to arrange those 6 people. The exclamation mark is a factorial symbol.

Within any of those 720 permutations, we have 4! = 4*3*2*1 = 24 ways to arrange those group of named people when they come back to replace the teacher.

So overall the answer is 4!*6! = 24*720 = 17,280

You may need to erase the comma when typing the answer in.

-------------

Side note: There are 9! = 362,880 ways to arrange all nine friends regardless if those four mentioned people stick together or not. We see that they stick together roughly (17,280)/(362,880) = 0.0476 = 4.76% of the time.

6 0
3 years ago
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