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3 years ago

Help me complete the square.

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

4 0

Answer:

k= $\sqrt{129}$ -10=1.357816691600547or k= $-\sqrt{129}$ -10=-21.35781669160055

Step-by-step explanation:

k^2-20k=29 |+100

k^2-20k+100=29=100

k^2-2x10xk+(-10)^2=129

(k-10)^2=129

|k-10|= $\sqrt{129}$

case 1 k is a positive number

case 2 k is a negative number

hope this helps

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4 years ago

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3 years ago

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3 years ago

Read 2 more answers

A triangle has a 60 degree angle, and the two adjacent sides are 12 and 12 times the square root of 3. Find the radius of a circ

Natasha_Volkova [10]

The radius of the circle is a line from the center of the circle to its circumference

The radius of the circle with the same vertex as a center is 10.16 units

<h3>How to determine the radius</h3>

From the question, we understand that:

The adjacent sides of the triangle are 12 and $12\sqrt 3$
The triangle has an angle of 60 degrees

Start by calculating the area of the triangle using:

$Area = 0.5ab\sin C$

So, we have:

$Area = 0.5 * 12 * 12\sqrt 3 *\sin (60)$

This gives

$Area = 0.5 * 12 * 12\sqrt 3 * \frac{\sqrt 3}{2}$

$Area = 108$

The arc divides the triangle into two equal regions.

So, the area of the arc is:

$Arc = 0.5 * Area = 0.5 * 108$

$Arc = 54$

Also, the area of the arc is:

$Arc = \frac{\theta}{360} * \pi r^2$

So, we have:

$Arc = \frac{60}{360} *3.14 * r^2$

Simplify

$Arc = 0.523 * r^2$

This gives

$0.523 * r^2 = 54$

Divide both sides by 0.523

$r^2 = 103.25$

Take the square roots of both sides

$r = 10.16$

Hence, the radius of the circle with the same vertex as a center is 10.16 units

Read more about circumcised triangles at:

brainly.com/question/4268382

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3 years ago

Help me complete the square. ​

Help me complete the square.