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zmey [24]
3 years ago
9

The probability of a car having to stop at light #1 on Main street is 40%. The probability that a car having to stop at light #2

, given that it had to stop at light #1, is 80%. What is the probability that a car has to stop at both light #1 and light #2? Answer CHoices: 0.32 0.50 0.64 0.8
Mathematics
1 answer:
fredd [130]3 years ago
6 0
720 starting off from the Main Street being 40 percent leading the child to explode into 720 pieces
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The Massachusetts State Lottery averages, on a weekly basis, a profit of 10.0 million dollars. The variability, as measured by t
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Probability that in a given week, the profits will be between 8 and 10.5 million dollars is 0.3674.

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Firstly, <em>Let X = weekly profits</em>

The z score probability distribution for is given by;

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Probability that, in a given week, the profits will be between 8 and 10.5 million dollars is given by = P(8 < X < 10.5) = P(X < 10.5) - P(X \leq 8)

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  P(X \leq 8) = P( \frac{ X - \mu}{\sigma} \leq \frac{8-10}{2.5} ) = P(Z \leq -0.8) = 1 - P(Z < 0.8)

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Therefore, P(8 < X < 10.5) = 0.57926 - 0.21186 = 0.3674

Hence, the chances that, in a given week, the profits will be between 8 and 10.5 million dollars is 0.3674.

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