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2 years ago

80+90=8+9 add a 0 to the end of your answer

Mathematics

1 answer:

Len [333]2 years ago

8 0

Answer:

The answer is 170

Step-by-step explanation:

Because 8 + 9 = 17, if we multiply all of these values by ten or add a zero to the end of each number, we should get

80 + 90 = 170

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Each angle of the equilateral triangle in the figure has measure (2x + 12)°. Find the value of x. answers: 24 39 12 84

Scorpion4ik [409]

Answer:

Step-by-step explanation:

Equilateral has 3 angles that add up to 180, and all angles are equal

3(2x+12) = 180

6x+36 = 180

180-36 = 6x

144 = 6x

24 = x

3 0

2 years ago

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Write a formula for g(x) in terms of x.

liberstina [14]

The formula of g(x) is g(x) = -0.8x - 1.6

<h3>How to determine the formula of g(x)?</h3>

The equation is given as:

-4x - 6 = 5y + 2

Subtract 2 from both sides

5y = -4x - 8

Divide through by 5

y = -0.8x - 1.6

Express as a function

g(x) = -0.8x - 1.6

Hence, the formula of g(x) is g(x) = -0.8x - 1.6

Read more about linear functions at:

brainly.com/question/4025726

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1 year ago

Question in attachment!

wolverine [178]

Answer:

y = 2x - 3

Step-by-step explanation:

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2 years ago

A 6-pack of batteries cost $10.50.what is the unit price

IRINA_888 [86]

Answer:

Unit price = $1.75

Step-by-step explanation:

In order to determine the unit price of the batteries, divide the $10.50 total price for the 6-pack of batteries by 6:

$10.50 ÷ 6 = $1.75

Therefore, the unit price of each battery is $1.75.

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2 years ago

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((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify

malfutka [58]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}$

$\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}
\\\\\\
\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}$

7 0

2 years ago