All categories

3 years ago

Rewrite the polynomial in the form ax^2 + bx + c then identify the values of a, b, and c

Mathematics

1 answer:

Jlenok [28]3 years ago

6 0

Answer:

$x^{2} -16$

a = 1

b=0

c= -16

i assume the next question is to factor that...

(x-4)(x+4)

Step-by-step explanation:

You might be interested in

The dot plot showed the number of flowers on a rosebush: 18, 18, 18, 18, 20, 20, 22, 23 The number 19 is used to summarize the d

Darya [45]

Answer:

19 measures the median

Step-by-step explanation:

The dot plot is not shown, but the question can still be answered.

We have:

$Samples: 18, 18, 18, 18, 20, 20, 22, 23$

$n = 8$

Calculate the median position using:

$Median = \frac{n + 1}{2}th$

$Median = \frac{8 + 1}{2}th$

$Median = \frac{9}{2}th$

$Median = 4.5th$

4.5th means the median is the mean of the 4th and 5th item.

We have:

$4th = 18$

$5th = 20$

So:

$Median = \frac{18 + 20}{2}$

$Median = \frac{38}{2}$

$Median = 19$

3 0

3 years ago

The perimeter of a scalene triangle is 14.5 cm. The longest side is twice that of the shortest side. Which equation can be used

wel

Answer:

$9.3 + b = 14.5$

Step-by-step explanation:

Longest side of ∆ = 2a = 6.2 cm

If the shortest side is, a, and we are told that the longest side is twice the shortest side, therefore, length of shortest side is

The sum of the 3 sides = perimeter = 14.5 cm

Thus,

$a + 2a + b = 14.5 cm$

Plug in the values of a and b

$3.1 + 6.2 + b = 14.5$

The equation that can be used to find the side lengths is $9.3 + b = 14.5$

7 0

4 years ago

WILL GAVE BRAINLIST!! Use the zero product proper to find the solutions to the equation x^2-x-6=0

Kruka [31]

(x-3)(x+2)=0

x= 3 and x= -2

5 0

3 years ago

Find the value for the following determinant.<br><br><br><br> -32<br> -42<br> 42

hjlf

Using the rule for 2x2 matrices,

$\begin{vmatrix}a&b\\c&d\end{vmatrix}=ad-bc$

the determinant for your matrix is

$\begin{vmatrix}5&-4\\8&2\end{vmatrix}=5\times2-(-4)\times8=42$

4 0

4 years ago

Read 2 more answers

Quick algebra 1 question for 10 points!

trasher [3.6K]

$m = m \\ \frac{97 - 68}{2 - 1} = \frac{134 - 97}{3 - 2} \\ 29 = 37 \\ this \: function \: is \: non \: linear$

<h3>Since the only two other options are quadratic and given that it must satisfy one of them i will assume the following general form of the function.</h3>

$f(1) = 68 \: \: \: f(2) = 97 \: \: \: \: f(3) = 134 \\ f(x) = ax {}^{2} + bx + c$

<h3>Substitute in the first function any point.</h3>

$f(1) = 68 \\ 7.8(1) {}^{2} - 2.9(1) + 67.1 = 68 \\ 7.8 - 2.9 + 67.1 = 68 \\ 72 = 68 \\ this \: is \: false$

<h3>I'm pretty sure something is wrong with the given</h3>

7 0

2 years ago