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Solnce55 [7]
3 years ago
11

Find A+B, A, B, C, or D.

Mathematics
1 answer:
klio [65]3 years ago
7 0

Answer: the answr is b because its divisble

Step-by-step explanation:

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5 less than a quotient of a number y and 2
mezya [45]

Start at the end and work backwards:

-- The quotient of a number 'y' and 2 . . . . .  ( y/2 )

-- 5 less than that . . . . .    ( y/2 - 5 )

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3 years ago
How do i become smarter in math class and im in 8th grade
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Answer:

I'm in 8th grade too, It's easy to pass math, Just take a screenshot of your hw, then submit it, My math teacher doesn't care if I just submit it.

Step-by-step explanation:

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3 years ago
Jenica has $4.50 in dimes and quarters. She has 1 more than three as many quarters as dimes. How many quarters does she have?
Zielflug [23.3K]

Answer:

Laura has $4.50 in dimes and quarters she has 3 more dimes than quarters How many quarters does she have

She has 3 more dimes than quarters. How many quarters does she have? Laura has 15 dimes and 12 quarters.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The length of the hypotenuse of the right triangle is 25 cm, the length of one of the legs is 10 cm. What is the length of the s
Anna007 [38]

Answer:

  21 cm

Step-by-step explanation:

Call the triangle ABC, with the right angle at B, the hypotenuse AC=25, and the given leg AB=10. The altitude to the hypotenuse can be BD. Since the "other leg" is BC, we believe the question is asking for the length of DC.

The right triangles formed by the altitude are all similar to the original. That means ...

  AD/AB = AB/AC . . . . . . ratio of short side to hypotenuse is a constant

Multiplying by AB and substituting the given numbers, we get ...

  AD = AB²/AC = 10²/25

  AD = 4

Then the segment DC is ...

  DC = AC -AD = 25 -4

  DC = 21 . . . . . centimeters

6 0
3 years ago
"a coin purse contains coins with values of 1 cent, 5 cents, 10 cents, 25 cents, and 50 cents. using each coin at least once, wh
cestrela7 [59]

Answer:

  11 coins for $1.99

Step-by-step explanation:

The maximum total less than $2 is $1.99. It takes 11 coins to make that total. It would take 1 fewer if the nickel were not required.

Starting with the minimum required coins, which total $0.91, we need to add $1.08 using a minimum number of coins. To minimize the added coins, we start with the largest we can use without going over the total: 2×50¢ + 1×5¢ + 3×1¢. These 6 coins added to the required 5 coins give the desired total using 11 coins.

  11 coins: $1.99 . . . . (3×50¢ +1×25¢ +1×10¢ +2×5¢ +4×1¢)

$1.99 is the highest possible total less than $2.00, and it takes a minimum of 11 coins to make that total.

4 0
3 years ago
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