7x+5=2x-35 What is the answer

1 answer:

5 0

7x + 5 = 2x - 35

=> 7x - 2x = - 35 - 5

=> x( 7 - 2 ) = - ( 35 + 5 )

=> x( 5 ) = - ( 40 )

=> x × 5 = - 40

$= >x = \frac{ - \cancel{40} \: \: \: ^{8} }{ \cancel{5}} \\ \\ \\ = > x = 5$

x = 5

Therefore the value of x in the given equation 5

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How do I factor x^4-5x^2+6?

Vilka [71]

Answer:

$=(x^2-3)(x^2-2)$

Step-by-step explanation:

So we have the expression:

$x^4-5x^2+6$

And we wish to factor it.

First, let's make a substitution. Let's let u be equal to x². Therefore, our expression is now:

$=u^2-5u+6$

This is a technique called quadratic u-substitution. Now, we can factor in this form.

We can use the numbers -3 and -2. So:

$=u^2-2u-3u+6$

For the first two terms, factor out a u.

For the last two terms, factor out a -3. So:

$=u(u-2)-3(u-2)$

Grouping:

$=(u-3)(u-2)$

Now, substitute back the x² for u:

$=(x^2-3)(x^2-2)$

And this is the simplest form.

And we're done!

3 0

2 years ago

Part 1. Please show work. Please assist me with these math problems.

Vitek1552 [10]

Answer: 1) 2, 3, 4, 9, 32, 279, 8896, 2481705, 22077238784

2) 2,490,924

3) Neither

<u>Step-by-step explanation:</u>

$S_n=S_{n-2}\cdot (S_{n-1}-1)\quad \\\\S_1=2\quad given\\S_2=3\quad given\\S_3=S_1(S_2-1)\quad =2(3-1)\quad =4\\S_4=S_2(S_3-1)\quad =3(4-1)\quad =9\\S_5=S_3(S_4-1)\quad =4(9-1)\quad =32\\S_6=S_4(S_5-1)\quad =9(32-1)\quad =279\\S_7=S_5(S_6-1)\quad =32(279-1)\quad =8,896\\S_8=S_6(S_7-1)\quad =279(8896-1)\quad =2,481,705\\S_9=S_7(S_8-1)\quad =8896(2481705-1)\quad =22,077,238,784$