Answer:
30 m/s
Step-by-step explanation:
Let's say the distance from the first car to the intersection is x, and the distance from the second car to the intersection is y.
The distance between the cars can be found with Pythagorean theorem:
d² = x² + y²
Taking derivative with respect to time:
2d dd/dt = 2x dx/dt + 2y dy/dt
d dd/dt = x dx/dt + y dy/dt
We know that x = 200, dx/dt = -25, y = 150, and dy/dt = -50/3.
To find dd/dt, we still need to find d.
d² = x² + y²
d² = (200)² + (150)²
d = 250
Plugging everything in:
250 dd/dt = (200) (-25) + (150) (-50/3)
dd/dt = -30
The cars are approaching each other at a rate of 30 m/s at that instant.
The interpretation of the given question is as follows:
Use the given inverse to solve the system of equations

The inverse of ![\left[\begin{array}{ccc}1&-1&1\\0&2&1\\3&-8&0\end{array}\right] is \left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-1%261%5C%5C0%262%261%5C%5C3%26-8%260%5Cend%7Barray%7D%5Cright%5D%20%20%20is%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-8%268%263%5C%5C-3%263%261%5C%5C6%26-5%26-2%5Cend%7Barray%7D%5Cright%5D)
x =
y =
z =
Answer:
x = - 1.5
y = - 0.5
z = - 5
Step-by-step explanation:
Using the correlation of inverse of matrix AX = B to solve the question above;
AX = B
⇒ A⁻¹(AX) = A⁻¹ B
X = A⁻¹ B
So ;
X = A⁻¹ B
![\left[\begin{array}{ccc}-6\\ -6\\- \dfrac{1}{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%5C%5C%20-6%5C%5C-%20%5Cdfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(-8*-6)+(8*-6)+(3*-\dfrac{1}{2})\\(-3*-6)+(3*-6)+(1*-\dfrac{1}{2})\\(6*-6)+(5*-6)+(-2* - \dfrac{1}{2})\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-8%2A-6%29%2B%288%2A-6%29%2B%283%2A-%5Cdfrac%7B1%7D%7B2%7D%29%5C%5C%28-3%2A-6%29%2B%283%2A-6%29%2B%281%2A-%5Cdfrac%7B1%7D%7B2%7D%29%5C%5C%286%2A-6%29%2B%285%2A-6%29%2B%28-2%2A%20-%20%5Cdfrac%7B1%7D%7B2%7D%29%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(48)+(-48)+(\dfrac{-3}{2})\\(18)+(-18)+(\dfrac{-1}{2})\\(-36)+(30)+(1)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%2848%29%2B%28-48%29%2B%28%5Cdfrac%7B-3%7D%7B2%7D%29%5C%5C%2818%29%2B%28-18%29%2B%28%5Cdfrac%7B-1%7D%7B2%7D%29%5C%5C%28-36%29%2B%2830%29%2B%281%29%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(\dfrac{-3}{2})\\(\dfrac{-1}{2})\\(-5)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28%5Cdfrac%7B-3%7D%7B2%7D%29%5C%5C%28%5Cdfrac%7B-1%7D%7B2%7D%29%5C%5C%28-5%29%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}-1.5\\-0.5\\ -5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1.5%5C%5C-0.5%5C%5C%20-5%5Cend%7Barray%7D%5Cright%5D)
Answer:
x=9
Step-by-step explanation:
Since the polygons are similar, the ratios of their respective sides are equal.
32/24=(x-1)/6
x-1=8
x=9
Answer:
64.3 lumens
Step-by-step explanation:
Data provided in the question:
Length of the testing chamber = 35 cm
Light at one end = 10 lumens
Light at other end = 200 lumens
now,
since the variation is linear,
therefore, the gradient of the variation
= 
= 5.43
also,
the darkest end is the end with 10 lumens
therefore,
The lumens at 10 cm from the darkest end
= 10 + 5.43(10)
= 10 + 54.3
= 64.3 lumens
To find a percentage, you the decimal point in the percent two places to the right 16% = 0.16. Then multiply.
0.16 • 400 = 64
16% of 400 = 64