Thickness measurements of a coating process are made to the nearest hundredth of a millimeter. The thickness measurements are un
iformly distributed with values 0.15, 0.16, 0.17, 0.18, 0.19. Determine the mean and variance of the coating thickness for this process. Round your answers to four decimal places (e.g. 98.7654).
(a) mean (in millimeters)
(b) variance (in millimeters2)
(a) Enter your answer in accordance to the item
a) of the question statement
(b) Enter your answer in accordance to the item
b) of the question statement
1 answer:
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Answer:
123 is the nearest value
The answer is infinite solutions.
subtract 50 from each side to get
23y+27y=50y
ad 23y and 27y to get 50y
50y=50y
and no matter what number you put in place you get the correct answer
Answer:
D!
Step-by-step explanation:
Answer:
C= 38 in Approx
A=113 in^2 Aprprox
Step-by-step explanation:
Given data
radius= 6 ft
Circumference, C=2πr
substitute
C=2*3.142*6
C=37.704 in
Area A= πr^2
substitute
A=3.142*6^2
A=3.142*36
A=113.112 in^2
The answer might be 39,600
