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3 years ago

Help please I am a bit confused on this.

Mathematics

2 answers:

son4ous [18]3 years ago

8 0

Good morning ☕️

____________________

Step-by-step explanation:

Look at the photo below for the answer.

Anit [1.1K]3 years ago

6 0

Because there are 4 inside angles the sum of the four angles must equal 360 degrees.

Add the angles to equal 360:

4x + 3x + 2x + 3x = 360

Simplify:

12x = 360

Solve for x by dividing both sides by 12:

x = 360 /12

x = 30

Now you have x, solve for each angle:

ABC = 4x = 4 x 30 = 120 degrees.

BCD = 3x = 3 x 30 = 90 degrees.

CDA = 2x = 2x 30 = 60 degrees.

DAB = 3x = 3 x 30 = 90 degrees.

C. It's important to know that a four sides figure needs the inside angles when added together need to equal 360 degrees.

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Help me please, I’m stuck!

Veseljchak [2.6K]

Answer:

5. (x, y) ⇒ (x +5, y +1)

6. (x, y) ⇒ (x +4, y -1)

Step-by-step explanation:

A translation rule will generally have the form ...

(x, y) ⇒ (x +h, y +k)

where (h, k) is the horizontal and vertical distance to the right and up that the figure is being translated.d

5) The image is 5 units right and 1 unit up from the original, so in the above formula, (h, k) = (5, 1) and the translation rule is ...

(x, y) ⇒ (x +5, y +1)

6) The image is 4 units right and 1 unit down from the original, so (h, k) = (4, -1) and the transformation rule is ...

(x, y) ⇒ (x +4, y -1)

4 0

3 years ago

What is the correct factorization of x^2 - 2x - 15?

iragen [17]

Answer:

option b

Step-by-step explanation:

${x}^{2} - 2x - 15$

${x}^{2} - 5x + 3x - 15 = 0$

$x(x - 5) + 3(x - 5) = 0$

$(x - 5)(x + 3) = 0$

x = -3 (Not possible)

x = 5

So, x = 5

8 0

2 years ago

Need help with graphing<br>

Paha777 [63]

Free points !!!!!!!!!!!

3 0

2 years ago

Suppose that a cyclist began a 476

mojhsa [17]

Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus $\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{eastbound cyclist}&d&r&8.5\\
\textit{westbound car}&476-d&r+33.2&8.5
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
\boxed{d}=8.5r\\\\
476-d=(r+33.2)8.5\\
----------\\
476-\boxed{8.5r}=(r+33.2)8.5
\end{cases}$

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2

6 0

3 years ago

Marvin rides his bike at an average speed of 13 miles per hour how far can he bike in 8 hours?

Radda [10]

13 x 8 = 104

104 miles

3 0

3 years ago

Read 2 more answers