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Rus_ich [418]
3 years ago
10

Help please I am a bit confused on this.

Mathematics
2 answers:
son4ous [18]3 years ago
8 0

Good morning ☕️

____________________

Step-by-step explanation:

Look at the photo below for the answer.

:)

Anit [1.1K]3 years ago
6 0

Because there are 4 inside angles the sum of the four angles must equal 360 degrees.

Add the angles to equal 360:

4x + 3x + 2x + 3x = 360

Simplify:

12x = 360

Solve for x by dividing both sides by 12:

x = 360 /12

x = 30

Now you have x, solve for each angle:

ABC = 4x = 4 x 30 = 120 degrees.

BCD = 3x = 3 x 30 = 90 degrees.

CDA = 2x = 2x 30 = 60 degrees.

DAB = 3x = 3 x 30 = 90 degrees.

C. It's important to know that a four sides figure needs the inside angles when added together need to equal 360 degrees.

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P(x) = √x


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for x = 4.41 → √4.41=  2.1 and p(4.41) = 2.1
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A lighthouse is located on a small island 5 km away from the nearest point P on a straight shoreline and its light makes seven r
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Step-by-step explanation:

Given:

Distance between island and point P = 5 km

Moving along the the shoreline when it is 1 km from P.

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From the above statement light makes seven revolutions per minute.

Therefore,              

\frac{d\theta}{dt}=\frac{7\times 2\pi\ rad}{1\ min}  = 14\pi\ rad/min  

Solution:

From the given figure.

tan\theta=\frac{x}{5}

Substitute x = 1

tan\theta=\frac{1}{5}  -------------------(1)

Now, first we differentiate both side with respect to t.

\frac{d(tan\theta)}{dt} = \frac{d}{dt}.(\frac{x}{3})

Using chain rule.

\frac{d(tan\theta)}{dt}.\frac{d\theta}{dt}  = (\frac{1}{5})\frac{dx}{dt}

sec^{2} \theta.\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}

(1+tan^{2} \theta).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}

Substitute tan\theta=\frac{1}{5} from equation 1.

(1+(\frac{1}{3})^{2} ).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}

(1+\frac{1}{9}).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}

Substitute \frac{d\theta}{dt}=14\pi

\frac{10}{9}.14\pi  = \frac{1}{5}.\frac{dx}{dt}

Applying cross multiplication rule.

\frac{dx}{dt}= \frac{700\pi }{9}

\frac{dx}{dt}= 77.78\pi

Therefore, light is moving along the shore at the speed of 77.78 km/min

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