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Rus_ich [418]
3 years ago
10

Help please I am a bit confused on this.

Mathematics
2 answers:
son4ous [18]3 years ago
8 0

Good morning ☕️

____________________

Step-by-step explanation:

Look at the photo below for the answer.

:)

Anit [1.1K]3 years ago
6 0

Because there are 4 inside angles the sum of the four angles must equal 360 degrees.

Add the angles to equal 360:

4x + 3x + 2x + 3x = 360

Simplify:

12x = 360

Solve for x by dividing both sides by 12:

x = 360 /12

x = 30

Now you have x, solve for each angle:

ABC = 4x = 4 x 30 = 120 degrees.

BCD = 3x = 3 x 30 = 90 degrees.

CDA = 2x = 2x 30 = 60 degrees.

DAB = 3x = 3 x 30 = 90 degrees.

C. It's important to know that a four sides figure needs the inside angles when added together need to equal 360 degrees.

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What number have the absolute value of 8
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4 0
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Read 2 more answers
Using bangle side relationship theorem use the angle measures to list the side lengths of the triangle in order from longest to
scoray [572]

Answer:

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BC=middle side

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6 0
3 years ago
Find the area of an isosceles trapezoid, if the lengths of its bases are 16 cm, and 30 cm, and the diagonals are perpendicular t
Klio2033 [76]
For this case we have:
 a = 30 cm
 c = 16 cm
 We look for the length of the diagonal:
 d = x + y
 Where,
 For x:
 a ^ 2 = x ^ 2 + x ^ 2
 x = a / root (2) = 30 / root (2) = 21.2132 cm
 For y:
 c ^ 2 = y ^ 2 + y ^ 2
 y = c / root (2) = 16 / root (2) = 11.3137 cm
 The diagonal is:
 d = x + y
 d = 21.2132 + 11.3137
 d = 32.5269 cm
 Then, the height is:
 h = h1 + h2
 For h1:
 h1 = root (x ^ 2 - (a / 2) ^ 2) = root ((21.2132) ^ 2 - (30/2) ^ 2)
 h1 = 15 cm
 For h2:
 h2 = root (y ^ 2 - (c / 2) ^ 2) = root ((11.3137) ^ 2 - (16/2) ^ 2)
 h2 = 8 cm
 Finally:
 h = h1 + h2
 h = 15 + 8
 h = 23 cm
 Then, the area is:
 A = (1/2) * (a + c) * (h)
 A = (1/2) * (30 + 16) * (23)
 A = 529 cm ^ 2
 Answer:
 
the area of an isosceles trapezoid is:
 
A = 529 cm ^ 2
4 0
2 years ago
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