To find out the answer of the two multiplied products with the help of partial products we separate into unit based numbers so as to, for easier calculation and simplification with units of zeroes. So, in this case we are given the product of 4 times of 652.
Here we need to expand this product of higher number to zeroes and take aside the added numbers to come back to the original multiple of a product. That is:
![\huge{652}](https://tex.z-dn.net/?f=%5Chuge%7B652%7D)
![\begin{bmatrix}652 \\ + \\ 0 \end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D652%20%5C%5C%20%2B%20%5C%5C%200%20%5Cend%7Bbmatrix%7D)
We just separated and expanded the product to be multiplied by removing other units following it. Same goes for other units at Hundredth, tenth and unitary position.
Therefore,
![\begin{bmatrix}600 \\ + \\ 52 \end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D600%20%5C%5C%20%2B%20%5C%5C%2052%20%5Cend%7Bbmatrix%7D)
For tenth term.
![\begin{bmatrix}50 \\ + \\ 2 \end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D50%20%5C%5C%20%2B%20%5C%5C%202%20%5Cend%7Bbmatrix%7D)
The terms after splitting and expanding the product before multiplication is:
![\begin{bmatrix}600 \\ 50 \\ 2 \end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D600%20%5C%5C%2050%20%5C%5C%202%20%5Cend%7Bbmatrix%7D)
Multiply the product elements in individual manner and add the elements forged by individual multiplication to get the required solution.
![\therefore \quad \begin{bmatrix}600 \times 4 \\ 50 \times 4 \\ 2 \times 4 \end{bmatrix}](https://tex.z-dn.net/?f=%5Ctherefore%20%5Cquad%20%5Cbegin%7Bbmatrix%7D600%20%5Ctimes%204%20%5C%5C%2050%20%5Ctimes%204%20%5C%5C%202%20%5Ctimes%204%20%5Cend%7Bbmatrix%7D)
![\begin{bmatrix}600 \times 4 \\ + \\ 200 \\ + \\ 2 \times 8 \end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D600%20%5Ctimes%204%20%5C%5C%20%2B%20%5C%5C%20200%20%5C%5C%20%2B%20%5C%5C%202%20%5Ctimes%208%20%5Cend%7Bbmatrix%7D)
![\begin{bmatrix}2400 \\ + \\ 200 \\ + \\ 2 \times 8 \end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D2400%20%5C%5C%20%2B%20%5C%5C%20200%20%5C%5C%20%2B%20%5C%5C%202%20%5Ctimes%208%20%5Cend%7Bbmatrix%7D)
![\begin{bmatrix}2600 \\ + \\ 8 \end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D2600%20%5C%5C%20%2B%20%5C%5C%208%20%5Cend%7Bbmatrix%7D)
![\boxed{\mathbf{Final \: \: Answer \: = \: 2,608}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cmathbf%7BFinal%20%5C%3A%20%5C%3A%20Answer%20%5C%3A%20%3D%20%5C%3A%202%2C608%7D%7D)
Hope it helps.
Answer:
y = 4x² - 4
Step-by-step explanation:
y = a(x - x₁ )(x - x₂)
Plug in the knowns
y = 4(x - 1)(x + 1)
expand
y = 4(x² - 1)
y = 4x² - 4
The answer is c for if you count the spaces in the half of brad, you get 4 and in half of kely, you get 8 which is a 2:1 ratio with kely and brad because kely's bigger
Answer:
<em>AC=16 inches</em>
Step-by-step explanation:
Given two side lengths of a triangle as x and y (x greater than y), the third side z must satisfy the inequality:
x - y ≤ z ≤ x + y
The side lengths are x=17 and y=10, thus:
17 - 10 ≤ z ≤ 17 + 10
7 ≤ z ≤ 27
The third side must be between 7 and 27 inches. The only choice that satisfies the conditions is AC=16 inches