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Lelechka [254]
3 years ago
11

24 % 89.5 % 10.5 % 76 %

Mathematics
2 answers:
lozanna [386]3 years ago
8 0

Answer:

89.5 %

Step-by-step explanation:

Leno4ka [110]3 years ago
3 0

Answer:

A

Step-by-step explanation:

I believe the answer is A. Good luck on your test!

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Use the Pythagorean theorem to find the distance between (-5,2) and (10,10)​
adelina 88 [10]

D^2 = (x2-x1)^2 + (y2-y1)^2

D =sqrt((10+5)^2 + (10-2)^2)

D P SQRT(15^2 + 8^2)

D = sqrt(225 +64)

D= sqrt(289)

D = 17

The distance is 17

3 0
3 years ago
Read 2 more answers
Help please. Thank you
Sav [38]

Step-by-step explanation:

use the formula and simply solve

6 0
2 years ago
Select all of the factors of x3 + 5x2 + 2x – 8.
gladu [14]

The factors of this polynomial would be (x + 4)(x + 2)(x - 1).


To find these, you first have to start with long division to find the first factor. If you use x + 4 it would look like this.


\frac{x^{3} + 5x^{2} + 2x - 8}{x + 4} = x^{2} + x - 2


Now we are left with only x^{2} + x - 2. We can factor this by looking for numbers that multiply to the last number and add to the middle number. 2 and -2 multiply to -2 and add to 1. Therefore, we'll use those in parenthesis in their place.


(x + 4)(x + 2)(x - 1)

5 0
3 years ago
Read 2 more answers
Find the height of the tree.
Burka [1]

Answer:

16 ft

Step-by-step explanation:

We start by converting 1yd to ft,

1yd = 3ft

So in the smaller triangle, we have 3ft, 4.5ft. Using Sine, Cos, and Tan rule. We know that

TanΦ = opposite / adjacent

TanΦ = 3ft / 4.5ft

TanΦ = 0.667

Φ = Tan^-1 0.6

Φ = 33.69

This means that the angle of elevation is 33.69°

Using this angle, and the same tan rule again, we gave

Tan 33.69 = opp/24

0.667 = opp/24

opp = 24 * 0.667

opp = 16 ft

5 0
3 years ago
Read 2 more answers
A 1 newton force will stretch a spring 1 meter. The spring/mass system is damped by a force that is 8 times the instantaneous ve
sukhopar [10]

Answer:

Step-by-step explanation:

Given the mass is m =16kg, and 1N force will stretch the spring 1 m.

That is, F =1N,Z =1m. Now find the spring constant k:

F = kL = 1 = k(1) = k= 1N/m.

The damping force is 8times the instantaneous velocity, this means β = 8,

and the external force is f(t) = 0

Initially the object compressed 0.6m above equilibrium position,

with the downward velocity is 2m/s.

The differential equation for a spring mass system with

damping force and extemal force is: mx" + βxt + kx = f(t).

so, 16x"+ 8x' + x= 0, x(0} = -0.6, x'(0)= 2m/s.

Now solve the DE:

The auxilary equation for the homogeneous equation is 16x"+8x'+x=0

solving we get, 16r² + 8r + 1 = 0 => (4r + 1)² = 0 => r = - 1/4.

Then the general solution for the homogenous system is: x(t)=c_1e^{-t/4} +c_2te^{-t\4}.

Use the initial conditions x (0) = -0.6, x'(0) = 2m/s:

x(0)=c_1e^{0} +c_2(0)e^{0}=-0.6=c_1\\x'(t)=-\frac{1}{4}c_1e^{-t/4}+c_2e^{-t/4}-\frac{1}{4}c_2te^{-t/4}\\x'(0)=-\frac{1}{4}c_1e^0+c_2e^0-\frac{1}{4}c_2(0)e^0=2=-\frac{1}{4}(-0.6)+c_2=c_2=1.85.

Hence, x(t) =-0.6e^{-t/4}+1.85te^{-t/4}.

5 0
3 years ago
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