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lilavasa [31]
3 years ago
13

Evaluate the integral \int (3t-2)/(t-1)dt please which method i should use

Mathematics
1 answer:
Natasha2012 [34]3 years ago
8 0
\dfrac{3t-2}{t-1}=\dfrac{3(t-1)+1}{t-1}=3+\dfrac1{t-1}

\displaystyle\int\frac{3t-2}{t-1}\,\mathrm dt=3\int\mathrm dt+\int\frac{\mathrm dt}{t-1}=3t+\ln|t-1|+C
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