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Shkiper50 [21]
3 years ago
5

A drawer is filled with 9 black shirts, 6 white shirts, and 5 gray shirts. One shirt is chosen at random from the drawer. Find t

he probability that it is not a white shirt.
Mathematics
2 answers:
artcher [175]3 years ago
8 0
Ok, I think this is the answer. 70% chance that it is Not a white shirt.
Ivahew [28]3 years ago
7 0

Answer: 0.7

Step-by-step explanation:

Given : A drawer is filled with 9 black shirts, 6 white shirts, and 5 gray shirts.

Total shirts in the drawer = 9+6+5=20

Number of shirts that are not white = 20-6=14

Now, the if one shirt is chosen at random from the drawer. then the probability that it is not a white shirt will be :-

\text{P(Not white)}=\dfrac{\text{Number of shirts not white}}{\text{Total shirts}}\\\\\=\dfrac{14}{20}=0.7

Hence, the required probability = 0.7

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(repost) Help Please I will Give brainliest If Correct!!
Eddi Din [679]

Answer:

There are about 7 x 10^6

Step-by-step explanation:

3.5*2029249= 7102347

rounds to 7000000= 7 x 10^6

6 0
2 years ago
Read 2 more answers
In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad
zysi [14]

Answer:  a) 0.0792   b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)   (1)

Similarly ,

P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0
3 years ago
Maria and her family drove 885 miles on their summer vacation . the first 8 on the left in this number has blank of 800
Anna71 [15]
The first 8 on the left in this number has a value of 800.
4 0
3 years ago
In a survey of 603 adults, 98 said that they regularly lie to people conducting surveys. Create a 99% confidence interval for th
marysya [2.9K]

Answer:

The population proportion is estimated to be with 99% confidence within the interval (0.1238, 0.2012).

Step-by-step explanation:

The formula for estimating the population proportion by a confidence interval is given by:

\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}

Where:

\hat{p} is the sample's proportion of success, which in this case is the people that regularly lie during surveys,

z_{\alpha /2} is the critical value needed to find the tails of distribution related to the confidence level,

n is the sample's size.

<u>First</u> we compute the \hat{p} value:

\hat{p}=\frac{successes}{n}=\frac{98}{603}=0.1625

<u>Next</u> we find the z-score at any z-distribution table or app (in this case i've used StatKey):

z_{\alpha /2}=2.576

Now we can replace in the formula with the obtained values to compute the confidence interval:

\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}=0.1625\pm 2.576\times\sqrt{\frac{0.1625\times(1-0.1625)}{603}}=(0.1238, 0.2012)

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3 years ago
Which of the following sets of numbers could represent the three sides of a
Alchen [17]

Answer:

im not sure if this is correct but, i got C

5 0
2 years ago
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