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professor190 [17]
3 years ago
6

A city in the Pacific Northwest recorded its highest temperature at 91 degrees Fahrenheit and its lowest temperature at 12 degre

es Fahrenheit for a particular year. Determine the class width if you wish to construct a frequency distribution with 7 classes.
Mathematics
1 answer:
Alina [70]3 years ago
3 0

Answer:

5x4;09 3x4

Step-by-step explanation:

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Which type of conic section is described by the following equation?​
krok68 [10]

Answer:

  C.  Hyperbola opening up and down

Step-by-step explanation:

A graph tells the tale.

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The term with the positive coefficient identifies the axis along which the hyperbola opens. Here, that is the y-axis, so the figure opens up and down.

The minus sign between the squared terms indicates it is a hyperbola, rather than a closed curve (ellipse or circle). The fact that both terms are squared indicates it is <em>not</em> a parabola.

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Find the reference angle for a rotation of 220°.
STatiana [176]

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ans is 40 degree

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3 years ago
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Translate the phrase into an algebraic explanation. the quotient of x and 5​
horsena [70]

Answer: \frac{x}{5} or x ÷ 5

Step-by-step explanation:

The quotient of x and 5 can be represented as \frac{x}{5} or x ÷ 5

4 0
2 years ago
40 PIONTS!!! HELP PLZ ANSWER THE QUESTIONS (IF YOU DONT ASWER THE QUETIONS THEN I WILL REPORT YOU)
allochka39001 [22]

Answer:

quadrant 1.

Step-by-step explanation:

A:(9,3)

B:(7,5)

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4 0
3 years ago
A department store will place a sale item in a special display for a one-day sale. Previous experience suggests that 43 percent
Svetradugi [14.3K]

Answer:

672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

Step-by-step explanation:

No. of customers pass the display on the day of sale = 1462

Proportion of people will purchase if pass such a special display = 0.43

Mean = E(X)=np

E(X)=1462 \times 0.43

E(X)=628.66

Standard deviation = \sqrt{npq}

Standard deviation =\sqrt{1462 \times 0.43 \times (1-0.43)}=18.92

Now we are supposed to find how many units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

P(X<x)=0.01

Using z table

P(\frac{x-\mu}{\sigma})= 2.33 \\\frac{x-628.66}{18.92}=2.33\\x=(2.33 \times 18.92)+628.66\\x=672.7436

Hence 672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

5 0
3 years ago
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