Answer:
(B) 0.038 M
Explanation:
Kc = [H2][I2]/[HI]^2
Let the equilibrium concentration of H2 be y M
From the equation of reaction, mole ratio of H2 to I2 formed is 1:1, therefore equilibrium concentration of I2 is also y M
Also, from the equation of reaction, mole ratio of HI consumed to H2 formed is 2:1, therefore equilibrium concentration of HI is (1 - 2y) M
1.6×10^-3 = y×y/(1 - 2y)^2
y^2/1-4y+4y^2 = 0.0016
y^2 = 0.0016(1-4y+4y^2)
y^2 = 0.0016 - 0.0064y + 0.0064y^2
y^2-0.0064y^2+0.0064y-0.0016 = 0
0.9936y^2 + 0.0064y - 0.0016 = 0
The value of y must be positive and is obtained by using the quadratic formula
y = [-0.0064 + sqrt(0.0064^2 - 4×0.9936×-0.0016)] ÷ 2(0.9936) = 0.0736 ÷ 1.9872 = 0.038 M
Answer:
Explanation:
Explanation: NA,Avogadro's number specifies 6.0221×1023 individual particles. It is simply another collective number like a dozen, or a score, or a gross. NA has the property that 6.0221×1023 individual cobalt atoms has a mass of 58.93⋅g
I think half-life of a radioisotope corresponds to the time taken by on-half of the atoms of a radioactive substance to disintegrate or decay. Half life measures the rate at which a radioactive isotope decays. Radioisotopes have various half lives which may range from a few microseconds to billion of years. For example the half life of potassium-40 is 1.3 billion years.
Pair of compounds have the same empirical formula :C₂H₂ and C₆H₆
<h3>Further explanation</h3>
Given
Carbon compound
Required
The same empirical formula
Solution
The empirical formula is the smallest comparison of atoms of compound forming elements.
A molecular formula is a formula that shows the number of atomic elements that make up a compound.
(empirical formula) n = molecular formula
C₂H₂ and C₆H₆
Empirical formula CH
(CH)₂=C₂H₂
(CH)₆=C₆H₆
C₂H₆ and C₃H₈
C₂H₆: Empirical formula CH₃
C₃H₈: Empirical formula C₃H₈
C₂H₅OH and CH₃OH ⇒ Empirical formula
CH₃CHO: Empirical formula : CH₃CHO
CH₃COOH: Empirical formula CH₂O
Answer:
0.086
Explanation:
A 5.2 molal aqueous solution of methyl alcohol indicates that 5.2 moles of methyl alcohol are present in 1 kilogram (or 1000 g) of water. Water has a molecular weight of 18 g/mol.
(100g)/18g/mol=55.56 mol
5.2 mol/(5.2mol+55.56 mol)=0.086
