Answer:
Number of moles = 0.05 mol
Explanation:
Given data:
Mass of Pb = 10.5 g
Number of moles of Pb = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of Pb is 207.2 g/mol.
Now we will put the values in formula.
Number of moles = 10.5 g/207.2 g/mol
Number of moles = 0.05 mol
Answer:
6 moles of SO₃ formed.
Explanation:
Given data:
Number of moles of SO₃ formed = ?
Number of moles of oxygen react = 3 mol
Solution:
Chemical equation;
2SO₂+ O₂ → 2SO₃
now we will compare the moles of oxygen and sulfur trioxide.
O₂ : SO₃
1 : 2
3 : 2/1×3 = 6 moles
Thus, six moles of SO₃ will formed.
Answer:
Molarity of sucrose = 0.116 M (Approx.)
Explanation:
Given:
Volume of solution = 0.5 liter
Mass of sucrose in gram = 20 gram
Molar mass of sucrose 342.3 g/mol
Find:
Molarity of sucrose
Computation:
Mole of sucrose = Mass of sucrose in gram / Molar mass of sucrose
Mole of sucrose = 20 / 342.3
Mole of sucrose = 0.058 (Approx.)
Molarity of sucrose = Mole of sucrose / Volume of solution
Molarity of sucrose = 0.058 / 0.5
Molarity of sucrose = 0.116 M (Approx.)
Answer:
3520 g of CO₂
Explanation:
2C₂H₆ + 70₂ → 4CO₂ + 6H₂O
molar ratio of the above reaction is;
2 : 7 → 4 : 6
2 moles of C₂H₆ will form 6 moles of H₂O
Thus, 1 mole of C₂H₆ will form 3 moles of H₂O
mass of H₂O = 360 g
molecular weight of H₂O = 18 g/mol
molar mass = mass ÷ molecular weight = 360÷18 = 20 moles
Total number of moles of H₂O formed = 6 * 20 moles = 120 moles
Number of moles of C₂H₆ reacted = 120 moles ÷ 3 = 40 moles
molar ratio of C₂H₆ to CO₂ = 1 : 2
Thus, number of moles of CO₂ formed = 2 * 40 moles = 80 moles
molecular weight of CO₂ = 44 g/mol
mass of CO₂ formed = number of moles x molecular weight = 80 * 44 = 3520 g