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Bess [88]
2 years ago
8

A 5.2 molal aqueous solution of methyl alcohol, CH3OH, is supplied. What is the mole fraction of methyl alcohol in the solution?

​
Chemistry
1 answer:
telo118 [61]2 years ago
4 0

Answer:

0.086

Explanation:

A 5.2 molal aqueous solution of methyl alcohol indicates that 5.2 moles of methyl alcohol are present in 1 kilogram (or 1000 g) of water. Water has a molecular weight of 18 g/mol.

(100g)/18g/mol=55.56 mol

5.2 mol/(5.2mol+55.56 mol)=0.086

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Need a quick answer!!!
Anna11 [10]
N: 60 mol
p: 20 atm = 20×1013hPa = 20260 hPa
T: 50°C = 323 K
R: 83,14 hPa·dm³/mol·K
V: ?
.................

pV = nRT
V = nRT/p
V = (60×83,14×323)/20260
V = 79,529 dm³ ≈ 79,6 dm³

79,6 dm³ = 79,6 L

:•)
7 0
3 years ago
What is the major driving force for losing a proton as the last step in an electrophilic aromatic substitution reaction?
Fofino [41]

Answer:

Explanation:

In the following reaction we have shown an example of aromatic substitution reaction .

C₆H₆ + RCl = C₆H₅R  + HCl

This  reaction takes place in the presence of catalyst like AlCl₃ which is a lewis acid .

First of all formation of carbocation is made as follows .

RCl + AlCl₃ = R⁺ + AlCl₄⁻

This R⁺ is carbocation which is also called electrophile . It attacks the ring to get attached with it .

C₆H₆ + R⁺  =   C₆H₅R⁺H.

The complex formed is unstable , though it is stabilized by resonance effect . In the last step H⁺ is kicked out of the ring . The driving force that does it is the steric hindrance due to presence of two adjacent group of H and R⁺ at the same place . Second driving force is attack by the base  AlCl₄⁻ that had been formed earlier . It acts as base and it extracts proton ( H⁺ ) from the ring .

C₆H₅R⁺H + AlCl₄⁻  = C₆H₆ + AlCl₃ + HCl .

The formation of a stable product C₆H₆ also drives the reaction to form this product .

4 0
3 years ago
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Vedmedyk [2.9K]

Answer: gas and alkaline earth metal

Explanation:

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matrenka [14]
2 meters per second. You do 10 divided by 5 to find your answer, which is 2.
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ZanzabumX [31]
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5 0
3 years ago
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