The cost of labour per hour is $90.56
The total amount paid by Austin is the sum of the total cost of labour and the cost of the parts
Total amount paid = total cost of labour + cost of parts
$553.50 = total cost of labour + $126
total cost of labour = $533.50 - $126
= $407.50
The total cost of labour = cost of labour per hour x total time worked
$407.50 = xx × 4.5
xx = $407.50 / 4.5
xx = $90.56
A similar question was solved here: brainly.com/question/21400699?referrer=searchResults
Answer:
y =-5/4x +11/2
Step-by-step explanation:
First we need to find the slope of the line
4x-5y = 10
Solve for y
Subtract 4x from each side
4x-4x-5y =-4x-10
-5y = -4x-10
Divide by -5
-5y/-5 = -4x/-5 -10/-5
y = 4/5x +2
The slope is 4/5
The slope of a line that is perpendicular is the negative reciprocal
m perpendicular = - (5/4)
We know have a slope = -5/4 and a point (2,3)
We can use the point slope form of a line
y-y1 = m(x-x1)
y-3 = -5/4 (x-2)
Distribute
y-3 =-5/4x +10/4
Add 3 to each side
y-3+3 = -5/4 x +5/2 +3
Get a common denominator
y = -5/4x +5/2 +6/2
y =-5/4x +11/2
Answer:
The answer is 65
Step-by-step explanation:
First, determine the x-value that corresponds to the given year.
Since x corresponds to the number of years since 2000, the year 2009 corresponds to an x-value of 9.
Next, find the y-value on the trend line that corresponds to an x-value of 9. The problem statement has been updated to show lines traced from the x-value of 9 to the trend line and then to the y-value.
Notice that the point (9,70) appears to lie on the trend line.
Therefore, in 2009, approximately 70 million passengers travelled through the airport.
Question is complete.
