Answer:
Step-by-step explanation:
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2
Adding and substracting 2x^2y^2
We get
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2
And we know a^2-2ab+b^2=(a-b)^2
So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2
Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2
And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2
Answer:
B
Step-by-step explanation:
Since the triangle is right use the tangent ratio to find x
tan64° = 
= 
Multiply both sides by 11
x = 11 × tan64° = 22.55 → B
If similarity ratio means the ratio between the lengths of the cubes:
![\frac{ L_1^{3} }{ L_2^{3} } = \frac{V_1}{V_2} \\ \\ ratio = \frac{L_1}{L_2} = \frac{\sqrt[3]{V_1} }{\sqrt[3]{V_2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%20L_1%5E%7B3%7D%20%7D%7B%20L_2%5E%7B3%7D%20%7D%20%3D%20%20%5Cfrac%7BV_1%7D%7BV_2%7D%20%20%5C%5C%20%20%5C%5C%20ratio%20%3D%20%20%5Cfrac%7BL_1%7D%7BL_2%7D%20%3D%20%20%20%5Cfrac%7B%5Csqrt%5B3%5D%7BV_1%7D%20%7D%7B%5Csqrt%5B3%5D%7BV_2%7D%20%7D%20)
Answer: B. 25%
Step-by-step explanation:
64-48 = 16
16/ 64= 0.25
0.25 x 100 = 25%
Answer:
A=51
a=22.2
c=28.6
Step-by-step explanation:
∠A=180-90-39
=51
a/sin51=18/sin39
a=22.2
c/sin90=18/sin39
c=28.6
