There are several ways you can solve this problem if you're trying to solve for m and n. You can substitute, or systems of equations. However, I'm going to use substitution:
2m + n = 0 => n = -2m
We can input that in for the other equation:
m + 2n = 3 now becomes: m + 2(-2m) = 3
Now we can solve:
m + 2(−2m) = 3
m + −4m = 3
(m + −4m) = 3 (Combine Like Terms)
−3m=3
m = -1
Now we can input that value in to solve for n:
We said that n = -2m, and m = -1, so n = -2(-1):Answer:
n = 2
Your final answer is m = -1, and n = 2, which can also be written as (m,n) = (-1,2)
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However, if you were solving for m+n:
You would add the two equations!:
2m + n = 0
m + 2n = 3
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3m + 3n = 3
Now, you can take 3 common:
3(m+n) = 3
m + n = 1
Your final answer for what m + n equals 1!
(2.7, 2.3)
(2, 1.7)
(1.7, 1.3)
again may be wrong
-4 = y + 3
y = -4x - 3
Solve for Y in the first equation:
-4 = y +3
Subtract 3 from both sides:
y = -7
Now using the addition method:
rewrite the second equation as 4x+y = -3
Multiply y = -7 by - 1 to get -y = 7
Now add the two together:
4x +y = -3
-y =7
4x = 4
Divide each side by 4:
x = 4/4 = 1
Then replace x in one of the equations to solve for y which is -7
X = 1, Y = -7
Can you take a picture of the problem?
