<u>Answer:</u> The mass of silver nitrate that must be dissolved is 1.58 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
......(1)
Given mass of silver = 1 g
Molar mass of silver = 107.86 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of silver nitrate and copper follows:
By Stoichiometry of the reaction:
2 moles of silver is produced from 2 moles of silver nitrate
So, 0.0093 moles of silver will be produced from = of silver nitrate
Now, calculating the mass of silver nitrate from equation 1, we get:
Molar mass of silver nitrate = 169.87 g/mol
Moles of silver nitrate = 0.0093 moles
Putting values in equation 1, we get:
Hence, the mass of silver nitrate that must be dissolved is 1.58 grams.