V(NaOH)*M(NaOH)=V(HCOOH)M(HCOOH)
35.43ml*0.1150m=20.00ml*M(HCOOH)
M(HCOOH)=0.2037m
Answer
0.9516 grams / mL (50.00 has 4 sig digs.)
Remark
You have a couple of extraneous numbers there. You don't care about anything except the mass of the flask + water/alcohol mixture (88.219 grams). and the mass of the flask (40.638 grams)
Formulas
- mass water/alcohol mixture = mass of the flask with fluid - mass flask
- density = mass / volume
Solution
mass water/alcohol mixture = 88.219 - 40.638 = 47.581
- Volume = 50 mL
- Density = mass / Volume
- Density = 47.581/50
- Density = 0.95162 There are 4 sig digs so the answer should be
- 0.9516
Answer: En estos grupos de los elementos de transición se encuentran las llamadas tierras raras, separadas del resto de elementos de la tabla, que pertenecen al grupo IIIB y se les conoce como lantánidos y actínidos.
Answer:
Since there are 3 Hydrogen atoms present, the formula mass of H is 1.0 × 3 = 3.0 g/mol. Therefore, by adding them up, the formula mass of ammonia is: [14.0 g/mol + 3.0 g/mol] = 17.0 g/mol.
The concentration of a and b will decrease while c will increase provided all other physical quantities are kept constant in the reaction
