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Mice21 [21]
3 years ago
15

11. Which is a set of similar fractions?

Mathematics
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

D. 2/10, 3/10, 4/10

Step-by-step explanation:

D. is the correct answer because the fractions have a common denominator of 10, whereas the other answer choices do no.

D. has similar fractions

Good luck to you!

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Find the range for the given domain: {-3,-1 and 3} and the function is y=3x^2-2x+1.
Artist 52 [7]

Answer:

D

Step-by-step explanation:

The domain are the x values. When you plug those values into the equation, you get 34, 6, 22.

3(-3²) - 2(-3) + 1                     Negative * Negative = Positive

3(9) + 6 + 1

34

3(-1²) - 2(-1) + 1

3 + 2 +1

6

3(3²) -2(3) + 1

3(9) - 6 + 1

22

7 0
2 years ago
Two sides of a triangle have lengths 11 and 18. Write an inequality to represent the possible lengths for the third side, x.
KatRina [158]
<span>Side inequality of triangle states that the sum of any two sides of a triangle should be greater than the third side so the sum of two sides

In this case, 11 + 18 = 29 > 3rd side So 29 > 3rd side or we can say 3rd side < 29

Also, the third side cannot be smaller than the difference of the given two sides so the third side has to be greater than 18-11 = 7 so 3rd side > 7 so if length of 3rd side is represented by x, then 7 < x < 29</span>
3 0
3 years ago
Read 2 more answers
Anyone here good at geometry ?!! I need help please!
vitfil [10]

Answer:

T must be 3/(3+1) or 3/4ths of the way between point d and f.

Take (dx, dy) and add 3/4 (fx-dx, fy-dy) by components and that will be point T (Tx, Ty)

You find the distances between d and f in x and y and then move 3/4 of that distance from d.

Step-by-step explanation:

Im not too sure, I got the answer from my last test. It might be wrong

7 0
2 years ago
Solve the following System of Three Equations: x−3y+z=−15<br> 2x+y−z=−2<br> x+y+2z=1
jeyben [28]

Answer:

x = -3 , y = 4 , z = 0

Step-by-step explanation:

Solve the following system:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for z:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Solve for z.

Subtract x - 3 y from both sides:

{z = 3 y + (-x - 15)

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Perform a substitution.

Substitute z = -15 - x + 3 y into the second and third equations:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

x + y + 2 (-15 - x + 3 y) = 1

Hint: | Expand the left hand side of the equation x + y + 2 (-15 - x + 3 y) = 1.

x + y + 2 (-15 - x + 3 y) = x + y + (-30 - 2 x + 6 y) = -30 - x + 7 y:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Isolate terms with x to the left hand side.

Subtract 15 - 2 y from both sides:

{z = -15 - x + 3 y

3 x = 2 y - 17

-30 - x + 7 y = 1

Hint: | Solve for x.

Divide both sides by 3:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

-30 - x + 7 y = 1

Hint: | Perform a substitution.

Substitute x = (2 y)/3 - 17/3 into the third equation:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Choose an equation and a variable to solve for.

In the third equation, look to solve for y:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Isolate terms with y to the left hand side.

Add 73/3 to both sides:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 = 76/3

Hint: | Solve for y.

Multiply both sides by 3/19:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

y = 4

Hint: | Perform a back substitution.

Substitute y = 4 into the first and second equations:

{z = -x - 3

x = -3

y = 4

Hint: | Perform a back substitution.

Substitute x = -3 into the first equation:

{z = 0

x = -3

y = 4

Hint: | Sort results.

Collect results in alphabetical order:

Answer: {x = -3 , y = 4 , z = 0

6 0
3 years ago
C•C (c=4) evaluating expressions
bearhunter [10]

Answer:

16

Step-by-step explanation:

if c = 4, then

(c)(c) = 16

if I misinterpreted your equation, please tell me.

5 0
3 years ago
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