The solution is 
<em><u>Solution:</u></em>
Let us assume,
<em><u>Given system of equations are:</u></em>
<em><u>Rewrite the equation using "a" and "b"</u></em>
2a - 3b = -5 ------------ eqn 1
4a + 6b = 14 -------------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Multiply eqn 1 by 2</u></em>
2(2a - 3b = -5)
4a - 6b = -10 ------------- eqn 3
<em><u>Add eqn 2 and eqn 3</u></em>
4a + 6b = 14
4a - 6b = -10
( - ) --------------------
8a = 4
Substitute a = 1/2 in eqn 1
Now let us go back to our assumed values
Substitute a = 1/2 in assumed values
Substitute b = 2 in assumed value
Thus the solution is
Well is just their sum, thus
Answer:
336
Step-by-step explanation:
Required Formulas:-
1. Number of ways to select x things out of n things = ⁿCₓ
2. Number of ways to arrange n things when a things and b things are similar = n!/(a!*b!)
Since we have to choose 8 colors and we are having 3 different colors, it is only possible when we select 2 different colors (e.g. 5 red and 3 blue). To find all possible ways we will have to find all unique arrangements of selected color.
Using formula (1), number of ways to select 2 colors out of given 3 colors = ³C₂ = 3
Using formula (2), finding all unique arrangements when 5 stripes are of one color and 3 stripes are of second color = 8!/(3!*5!) = 56
Suppose, we can choose 5 stripes from red color and 3 stripes from blue color or 5 strips from blue color and 3 strips from red color. So there are 2 possibilities of arranging every 2 colors we choose .
∴ Answer=3*56*2 = 336
Answer:
we can’t see correctly
take another screen shot and ask the question again
Answer:
A or D is the answers for the question
Step-by-step explanation:
please give me brainlest and follow me
