This is distance formula is sqr. root of (x1-x2)^2 + (y1-y2)^2
(3-(-4))^2+ (-94-(-195))
7^2 101^2
49+ 10,201
square root of 10250
101.242 or the closest answer to this
Answer:
class boundaries are the end points of an open interval which contains the class interval such that the lower class boundary (LCB) is the LCL minus one-half the tolerance and the upper class boundary (UCB) is the UCL plus one -half the tolerance.
Answer:
D. Divide both sides by - 8
Step-by-step explanation:
-8x = 312
x = 312/(-8)
x = - 39
