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3 years ago

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Mathematics

1 answer:

pshichka [43]3 years ago

8 0

Answer:

the distance between the 2 points is 6.4 units.

Step-by-step explanation:

point 1 has the coordinates (-4, -2).

point 2 has the coordinates (1, 2).

the distance between both points is the Hypotenuse of the right- angled triangle of the coordinate difference lines in parallel to x- and y-axis.

so, how long is the difference in x dimension ?

and his long is the difference in y dimension ?

these are the sides of the triangle.

the difference in x dimension :

1 - -4 = 1 + 4 = 5

the difference in y dimension :

2 - -2 = 2 + 2 = 4

P1P2² = 4² + 5² = 16 + 25 = 41

P1P2 = sqrt(41) = 6.4

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Help me plz !!!!! Plz plz

Serjik [45]

Total weight of the steel gate = 150 kg

Solution:

Length = 12 m

Breadth = 5 m

Using Pythagoras theorem,

Diagonal = $\sqrt{l^2+w^2}$

$=\sqrt{12^2+5^2}$

$=\sqrt{144+25}$

$=\sqrt{169}$

Diagonal = 13 m

Total length of the gate = 5 + 5 + 12 + 12 + 13 + 13

Total length of the gate = 60 m

Weight of the steel per meter = 2.5 kg

Weight of the steel for 60 m = 60 × 2.5

= 150 kg

Total weight of the steel gate = 150 kg

8 0

4 years ago

Can someone help me with this can’t come up with the right answer

Georgia [21]

Answer:

exact form

13/4

Decimal form

3.25

mixed number form

3 1/4

7 0

3 years ago

When you move a circle vertically, the number that is part of the yterm<br> changes.

svetlana [45]

Answer:

Step-by-step explanation:

The general equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2. You seem to be referring to "the y-coordinate of the center of the circle," that is, h in (h, k).

Yes, if you move a circle vertically, the y-coordinate of the center changes.

It's unclear what you're asking for help with. Please try to be more specific next time.

3 0

3 years ago

Read 2 more answers

storchak [24]

Answer:

05949494

Step-by-step explanation:

;_;_;_(*(*!$+$+$8 djdjskosjdhdhdjdhdjsisudjjddhjdhdhhdhdhjhs the way to sk it or to did I rnd

5 0

3 years ago

If log10(x^{2}y^{3})=7 and log10 (x/y)=1 , then x=__ and y= __

yuradex [85]

Answer:

$x=100$

$y=10$

Step-by-step explanation:

we are given

$log_1_0(\frac{x}{y})=1$

Firstly, we will get rid of log

so, we will take exponent over 10 on both sides

$10^{log_1_0(\frac{x}{y})}=10^{1}$

now, we can simplify it

$\frac{x}{y}=10$

now, we can solve for x

$x=10y$

we are given

$log_1_0(x^2y^3)=7$

Firstly, we will get rid of log

so, we will take exponent of 10 on both sides

$10^{log_1_0(x^2y^3)}=10^7$

$x^2y^3=10^7$

now, we can plug back x from first equation

$(10y)^2y^3=10^7$

now, we can solve for y

$100y^5=10000000$

$\frac{100y^5}{100}=\frac{10000000}{100}$

$y^5=100000$

now, we can take radical 5

$y=\sqrt[5]{100000}$

$y=10$

now, we can find x

$x=10\times 10$

$x=100$

So, solution is

$x=100$

$y=10$

4 0

4 years ago