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3 years ago

15

I don’t get it please can I have help :)

2 answers:

RideAnS [48]3 years ago

7 0

Answer:

${7}^{2} \times \sqrt[3]{7}\\ = {7}^{2} \times {7}^{ \frac{1}{3} } \\ = {7}^{(2 + \frac{1}{3}) } \\ = {7}^{ \frac{(6 + 1)}{3}} \\ = \boxed{{7}^{ \frac{7}{3}}}✓$

<h3><u>7⁷/³</u> is the right answer.</h3>

Irina-Kira [14]3 years ago

4 0

7^2 x cube root 7
= 7^2 x 7^1/3
= 7^2+1/3
= 7^7/3

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miss Akunina [59]

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Options (1), (2), (3) and (7)

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$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

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