Question

I don’t get it please can I have help :)

Answer 1

Answer:

${7}^{2} \times \sqrt[3]{7}\\ = {7}^{2} \times {7}^{ \frac{1}{3} } \\ = {7}^{(2 + \frac{1}{3}) } \\ = {7}^{ \frac{(6 + 1)}{3}} \\ = \boxed{{7}^{ \frac{7}{3}}}✓$

7⁷/³ is the right answer.

Answer 2

7^2 x cube root 7
= 7^2 x 7^1/3
= 7^2+1/3
= 7^7/3