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Aleonysh [2.5K]
3 years ago
12

Jessie is participating in a walkathon to raise

Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0

Jessie needs 27 supporters in order to reach his goal.

Step-by-step explanation:

Given,

Amount to be collected by Jessie = $150

Jessie's contribution = $15

Amount to be asked from each person = $5

Let,

x be the number of people who contribute.

Jessie's contribution + 5*Number of people who contribute = Total amount

15+5x=150

Subtracting 15 from both sides

15-15+5x=150-15\\5x=135

Dividing both sides by 5

\frac{5x}{5}=\frac{135}{5}\\x=27

Jessie needs 27 supporters in order to reach his goal.

Keywords: linear expression, division

Learn more about division at:

  • brainly.com/question/4655616
  • brainly.com/question/4694425

#LearnwithBrainly

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4 years ago
Find all the zeros of the equation x^4-6x^2-7x-6=0 Explain please.
Alina [70]
<h3>Answer:</h3>
  • zeros are {-2, 3, (-1±i√3)/2}
<h3>Step-by-step explanation:</h3>

I like to look at a graph of the function to see where the zeros might be. Here, there are x-intercepts at x=-2 and x=3. These can be factored out using synthetic division to find the factorization to be ...

... (x +2)(x -3)(x² +x +1) = 0

By completing the square, using the quadratic formula, or by looking at the graph of it, the complex roots of the quadratic factor can be found to be ...

... x = (-1 ±i√3)/2

_____

The second attachment shows my synthetic division. The first division takes out the root x=3 to give a quotient of x³ +3x² +3x +2. The second division takes out the root -2 to give the quotient of x² +x +1. (You can see that I tried -1 as a root first.)

The graph shows both the quartic and the quadratic factor of it. The latter has a leading coefficient of 1 and a vertex at (-1/2, 3/4), so you know the complex roots are -1/2 ±i√(3/4).

_____

<em>From the beginning</em>

There is only a very complicated formula for the roots of a quartic equation, so these are usually solved by machine or by some form of trial and error (iteration). There are some helps, like Descarte's Rule of Signs, and the Rational Root theorem.

Here, the former looks at the one sign change in the coefficients to tell you there will be 1 positive real root. Changing the sign of the odd-degree terms makes there be 3 sign changes, so there will be 3 or 1 negative real roots. Thus, we're assured at least two real roots, one of each sign.

We can look at the constant term to find the y-intercept to be -6. We can add the coefficients to find the value of the function is -18 for x=1, so the positive real root is larger than 1.

The Rational Root theorem says any rational roots will be factors of 6, the constant term. Choices are 1, 2, 3, 6. We have already eliminated 1 as a possibility, and we consider it unlikely that 6 will be a root. (The 4th power overwhelms the other terms in the function.) We tried 2 and found it doesn't work (this was before we graphed the function). The attached division result shows that 3 is a root, as does the graph.

Once you get down to a quadratic, you can find the remaining roots in the usual way. Because it is so simple to read them from the graph, we decided to graph the quadratic factor.

_____

<em>Comment on terminology</em>

"root" and "zero" are essentially the same thing when the function is equated to zero, as here. The terms refer to the value(s) of x that make the polynomial function evaluate to zero.

8 0
3 years ago
HELP PLS ‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎ ‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎
VikaD [51]

Answer:

with what 0-0 are youy okay?

Step-by-step explanation:

8 0
3 years ago
30 points please..I will report your answer if not right Thanks​
ella [17]
<h3>Answer:  SAS</h3>

=================================

How to get this answer:

We're told that AD = BC, so that is one pair of sides that are congruent. This forms the first "S" in "SAS"

The "A" refers to the congruent angles, which happen to be angle DAB and angle CBA, both are 90 degrees

The second "S" in "SAS" is the second pair of congruent sides. Those two sides are the overlapping shared side of AB. It might help to peel the two triangles apart to get a better look.

Note how the angles are between the two pairs of sides mentioned.

4 0
3 years ago
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